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3 years ago

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if revenue for the week is 2000 and labor cost consist of two workers earning $8 per hour who work 40 hours each week what is la

bor cost as a percentage of revenue

1 answer:

DerKrebs [107]3 years ago

5 0

The Answer is 32%.
Because for two workers for 40 hours each, it will cost 640
and when you do .32*2000 it equals 640 also
Hope I helped :)<span />

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Please i need help asap

Mademuasel [1]

You would have to divide the categories over the budget. after you divide, you would end up with a decimal, so you to convert it into a percentage, you would simply multiply it by 100.

clothing: 6%
housing: 22%
insurance: 8%

8 0

2 years ago

Read 2 more answers

What is the average rate of change of the function f(x) = 5x ^ 2 + 20x between x = 0 and x = 0.5

Vitek1552 [10]

9514 1404 393

Answer:

22.5

Step-by-step explanation:

The average rate of change on the interval [a, b] is the ratio ...

(f(b) -f(x))/(b -a)

For your function and interval, it is ...

(f(0.5) -f(0))/(0.5 -0)

Since f(0) = 0, this reduces to ...

average rate of change = 2·f(0.5) = 2(5(0.5)² +20(0.5)) = 2(5/4 +10)

average rate of change = 22.5

8 0

3 years ago

last week, Jim worked h hours and earned $9 per hour. if he earned a total of $405, which equation can be used to find out how m

ad-work [718]

I hope this helps you

if he can earn $9 per hour

$405 ? hours

?=405/9

?=45 hours he worked

8 0

3 years ago

Two families go to a zoo.

ohaa [14]

Children ticket price=£9
Adult ticket price=£17
Let adult=A
Children=C
So, 2A+3C=61 (equation 1)
3A+5C=96(equation 2)
Multiply equation 1 by 3 and equation 2 by 2
Solve equations and get the answer.

5 0

2 years ago

Find a solution x = x(t) of the equation x′ + 2x = t2 + 4t + 7 in the form of a quadratic function of t, that is, of the form x(

Temka [501]

The particular quadratic solution to the ODE is found as follows:

$x=at^2+bt+c$
$x'=2at+b$

$(2at+b)+2(at^2+bt+c)=t^2+4t+7$
$2at^2+(2a+2b)t+(b+2c)=t^2+4t+7$

$\begin{cases}2a=1\\2(a+b)=4\\b+2c=7\end{cases}\implies a=\dfrac12,b=\dfrac32,c=\dfrac{11}4$

Note that there's also the fundamental solution to account for, which is obtained from the characteristic equation for the ODE:

$x'+2x=0\implies r+2=0\implies r=-2$

so that $x_c=Ce^{-2t}$ is a characteristic solution to the ODE, and the general solution would be

$x=Ce^{-2t}+\dfrac{t^2}2+\dfrac{3t}2+\dfrac{11}4$

4 0

3 years ago