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2 years ago

Accidentally checked in help me plz!!!!!!

Mathematics

2 answers:

Sergio [31]2 years ago

4 0

Answer:

It is 1/4!

Step-by-step explanation:

Because if you 4 1/4 will equal 1 now do that until you reach 16 then add two 1/4 then you will get you answer.

Please mark me as Brainiest.

And please let me know if you got it correct im curious.

Thank You!:)

Glad to Help!

BTW sorry if you did not understant my explanation.

eimsori [14]2 years ago

3 0

Answer: 4

Step-by-step explanation:

$16^{\frac{1}{2}}=\sqrt{16}=\sqrt{4\cdot 4}=\boxed{4}$

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Another way to express 42+24

kobusy [5.1K]

40 plus 26!!!!!!!! Like legit

4 0

3 years ago

Read 2 more answers

Which equation correctly shows how to determine the distance between the points (9, –2) and (6, 3) on a coordinate grid?

dybincka [34]

Hint: $\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 9}}\quad ,&{{ -2}})\quad 
% (c,d)
&({{ 6}}\quad ,&{{ 3}})
\end{array}\qquad 
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}$

3 0

3 years ago

For some reason it says square but please help! I need to know step by step what to do.

quester [9]

Answer:

8.06 inches

Step-by-step explanation:

The diagram shows a rectangle with width of 4 inches and area of 28 square inches.

Use area formula:

$A_{\text{rectangle}}=\text{Width}\times \text{Length}$

So,

$28=4\times \text{Length}\Rightarrow \text{Length}=\dfrac{28}{4}=7\ \text{inches}$

By the Pythagorean theorem,

$\text{Diagonal}^2=\text{Width}^2+\text{Length}^2\\ \\\text{Diagonal}^2=4^2+7^2\\ \\\text{Diagonal}^2=16+49\\ \\\text{Diagonal}^2=65\\ \\\text{Diagonal}=\sqrt{65}\approx 8.06\ \text{inches}$

7 0

2 years ago

Can someone please explain how to do this!!!

DedPeter [7]

Hi there!

So we are given that:-

tan theta = 7/24 and is on the third Quadrant.

In the third Quadrant or Quadrant III, sine and cosine both are negative, which makes tangent positive.

Since we want to find the value of cos theta. cos must be less than 0 or in negative.

To find cos theta, we can either use the trigonometric identity or Pythagorean Theorem. Here, I will demonstrate two ways to find cos.

Using the Identity

$\large \displaystyle{ {tan}^{2} \theta + 1 = {sec}^{2} \theta}$

Substitute tan theta = 7/24 in.

$\large \displaystyle{ {( \frac{7}{24}) }^{2} + 1 = {sec}^{2} \theta }$

Evaluate.

$\large \displaystyle{ \frac{49}{576} + 1 = {sec}^{2} \theta} \\ \large \displaystyle{ \frac{625}{576} = {sec}^{2} \theta}$

Reminder -:

$\large \displaystyle{ sec \theta = \frac{1}{cos \theta} }$

Hence,

$\large \displaystyle{ \frac{576}{625} = {cos}^{2} \theta} \\ \large \displaystyle{ \sqrt{ \frac{576}{625} } = cos \theta} \\ \large \displaystyle{ \frac{24}{25} = cos \theta}$

Because in QIII, cos<0. Hence,

$\large \displaystyle \boxed{ \blue{cos \theta = - \frac{24}{25} }}$

Using the Pythagorean Theorem

$\large \displaystyle{ {a}^{2} + {b}^{2} = {c}^{2} }$

Define c as our hypotenuse while a or b can be adjacent or opposite.

Because tan theta = opposite/adjacent. Therefore:-

$\large \displaystyle{ {7}^{2} + {24}^{2} = {c}^{2} } \\ \large \displaystyle{49 + 576 = {c}^{2} } \\ \large \displaystyle{625 = {c}^{2} } \\ \large \displaystyle{25 = c}$

Thus, the hypotenuse side is 25. Using the cosine ratio:-

$\large \displaystyle{cos \theta = \frac{adjacent}{hypotenuse}}$

Therefore:-

$\large \displaystyle{cos \theta = \frac{24}{25} }$

Because cos<0 in Q3.

$\large \displaystyle \boxed{ \red{cos \theta = - \frac{24}{25} }}$

Hence, the value of cos theta is -24/25.

Let me know if you have any questions!

8 0

2 years ago

You need to construct fence around an area of 3136 ft2. What are the dimensions of the rectangular pen that minimize the amount

borishaifa [10]

Answer:

Step-by-step explanation:

The the area of the rectangular pen be A = LW

L is the length

W is the width

Given

A = 3136ft²

3136 = LW..........1

Given the perimeter P = 2L+2W....... 2

From 1; L = 3136/W

Substitute into 2

P = 2(3136/W)+2W

P = 6272/W + 2W

In order to minimize the amount of material needed, then dP/dW = 0

dP/dW = -6272/W² + 2

0 = -6272/W² + 2

6272/W² = 2

cross multiply

6272 = 2W²

W² = 3136

W = √3136

W = 56ft

Since A = LW

3136 = 56L

L = 3136/56

L = 56ft

Hence the dimensions of the rectangular pen that minimize the amount of material needed is 56ft by 56ft

7 0

2 years ago