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Kipish [7]
3 years ago
12

a plane has 32 seats in class A and 50 seats in class B whose sale represents a total of € 14,600. However, only 10 seats have b

een sold in class A and 40 seats in class B. A total of € 7,000 was obtained What is the price of a seat in each class?
Mathematics
1 answer:
slavikrds [6]3 years ago
7 0
The two equations would be

32a+50b=14600
10a+40b=7000
To solve, we need to eliminate one variable.... let’s eliminate b

4(32a+50b=14600) —> 128a+200b=58400
-5(10a+40b=7000) —> -50a-200b=-35000
So when we add them together’ we get 78a = 23400
So solve that and a= 300, so class a tickets cost 300 euros each

Substitute a=300 into first equation in the system of equations at the beginning and 32(300)+50b=14600 —> 9600+50b=14600 —> 50b = 5000 or b= 100, so the cost for class b tickets is 100 euros each
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3 years ago
A theater group made appearances into cities the hotel charge before tax and the second city was 1500 higher than the first the
Svetlanka [38]

Answer:

The hotel charge in each city before tax was <u>$5125</u> of the first city and <u>$3625</u> of the second city.

Step-by-step explanation:

Given:

A theater group made appearances into cities the hotel charge before tax and the second city was 1500 higher than the first.

The tax of the first city was 6% and the tax of the second city was 10%.

Total hotel tax paid for two cities with $670.

Now, to find the hotel charge in each city before tax.

Let the hotel charge in first city before tax be x.

And the hotel charge in second city before tax be y.

<em>So, as the hotel charge of the second city was 1500 higher than the first.</em>

<em>Thus</em>,

y=x-1500   ........(1)

<em>And as given, the tax of the first city was 6% and the tax of the second city was 10%, total hotel tax paid for two cities with $670.</em>

6% of x + 10% of y = $670.

\frac{6x}{100} +\frac{10y}{100} =670

0.06x+0.10y=670

Substituting the value of y from equation (1) we get:

0.06x+0.10(x-1500)=670

0.06x+0.10x-150=670

0.16x-150=670

<em>Adding both sides by 150 we get:</em>

0.16x=820

<em>Dividing both sides by 0.16 we get:</em>

x=5125.

<em>The hotel charge in first city before tax = $5125.</em>

Now, substituting the value of x in equation (1) we get:

y=x-1500

y=5125-1500

y=3625.

<em>The hotel charge in second city before tax = $3625.</em>

Therefore, the hotel charge in each city before tax was $5125 of the first city and $3625 of the second city.

5 0
4 years ago
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