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leva [86]
3 years ago
14

Slope of (-7,-2) (9,4)

Mathematics
1 answer:
Olenka [21]3 years ago
4 0

Answer:

m= \frac{3}{8}

Step-by-step explanation:

1. Use the slope equation to solve the problem

\frac{y_{2} -y_{1}}{x_{2} -x_{1} }

2. Plug in your values into the equation.

\frac{4-(-2)}{9-(-7)}

3. Simplify the equation.

m= \frac{3}{8}

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What is the area of a triangle with a base of 50 feet and a height of 75 feet’
inysia [295]

Answer:

The correct answer is,

the area of given triangle = 1875 square feet

Step-by-step explanation:

Formula:

Area of triangle = bh/2

b - Base and h - height

It is given that,a triangle with a base of 50 feet and a height of 75 feet’

<u>To find the area of triangle</u>

base b = 50 feet and height h = 75 feet

Area = bh/2 = (50 x 75 )/2

Area = 3750/2 = 1875 square feet

Therefore the area of given triangle = 1875 square feet

8 0
3 years ago
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Use the equation below to find c, if a = 39 and b= 27.<br> c=180-a-b<br> c=0<br> X<br> 5 ?
vfiekz [6]

Answer:

the answer is 114

Step-by-step explanation:

7 0
2 years ago
What do I need to do to do well in Algebra II?
GaryK [48]
Ask your teacher for help or watch a video that would help or do research and study
8 0
3 years ago
(1) 16 liters of kerosene is needed for 12 stoves 14
Nastasia [14]

9514 1404 393

Answer:

  12 liters

Step-by-step explanation:

The kerosene usage is assumed to be jointly proportional to the number of stoves and the number of hours. That is ...

  v = k·s·h . . . . . for s stoves running h hours

Then the value of k is ...

  k = v/(sh) = (16 L)/(12·14) = 2/21 . . . . liters per stove-hour

Then the volume of kerosene required for 7 stoves and 18 hours is ...

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6 0
2 years ago
¿Cuántos quilómetros recorrerá una locomotora en 5 horas, si marcha a una velocidad de 82 kilómetros
kicyunya [14]

Step-by-step explanation:

Datos;

una locomotora

recorre 5 horas

a una velocidad de 82 km/h

Se asume que la locomotora lleva un movimiento rectilíneo uniforme.

Su recorrido esta descrito por la siguiente ecuación de posición;

x = x₀+ v · t

x-x₀ = d = v · t

siendo;

d = distancia recorrida

v = 82 km/h

t = 5 horas

Sustituir:

d = (82)(5)

d = 410 km

82km/h * 5h= 410km

La locomotora recorrerá 410km

6 0
3 years ago
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