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devlian [24]
4 years ago
10

The length of a rectangle is 4 centimeters more than the width.if both the width and the length were tripled,the area would be 1

08 square centimeters.find the dimensions of the rectangle.
Mathematics
1 answer:
Sonbull [250]4 years ago
3 0
Since both the length and the width are tripled, the area will be nine times larger.  To counter this, divide by nine.  108/9=12  Divide this by 2 to get one length and one width.  You get 6.  1+5=6 and 1 is 4 smaller than 5, so the width of this rectangle is 1 cm and the length is 5 cm.  
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denis-greek [22]

Answer:

1 5 10 10 5 1

Step-by-step explanation:

The complete question has been attached as an image.

Looking at the triangle, we see a pattern. The first level we have 1, in the next level we have 1 1, the next evel we have 1 2 1, the next level we have 1 3 3 1 and so on. From here, we see that to get the numbers of the next level, we have to write 1 as the first number, then add 1 to the next number after it in the previous level to get the second number in the next level then add the second number of the previous level to the next number beside it to get the third number in the next level and so on until you get to the last number before 1 in the previous level, add that number to 1 to get the second to the last number in the next level and finally put 1 as the last number in the next level. Now, we have

1 4 6 4 1

1 5 10 10 5 1

And that is the required set of numbers.

3 0
3 years ago
What is between 68 2/3 and 72 1/2 (options) 68 3/10, 747/11, 68 1/2, 550/8
enyata [817]
Why not write all of the numbers in decimal fraction form, to make them easier to compare?

68 2/3 = 68.666...
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68 1/2  = 68.500
550/8 = 68.750

Now ask yourself:  Which of the last four numbers is between 68.666.. and 72.500?
3 0
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Answer:

67

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67

8 0
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Step-by-step explanation:

Rhombus has that equiangular and is equilateral but I'm not entirely sure about this...

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