If there are two points, there is always one line?

Mathematics

2 answers:

Kobotan [32]3 years ago

7 0

Answer:

Through any two points there exists exactly one line. A line contains at least two points. If two lines intersect, then their intersection is exactly one point. Through any three non-collinear points, there exists exactly one plane.

Step-by-step explanation:

butalik [34]3 years ago

3 0

Answer:

yes they are

Step-by-step explanation:

You might be interested in

Sos HELP MEEEEE I HAVE NO CLUE PLZ EXPLAIN !!!

OleMash [197]

2,376 square feet
**
Add the areas of all the sides of the shape.
A triangle's area: 1/2bh
The two triangles' area=24*9=216
The bottom side: 40*24=960
The two other sides: 30*40=1200
Add everything: 216+960+1200=2376

5 0

4 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7Bx%7D%20%2B1%7D%7Bx-%5Csqrt%7Bx%7D%20%2B1%7D" id="TexFormula1" title="\frac

zubka84 [21]

Answer:

Step-by-step explanation:

$\frac{\sqrt{x}+1 }{x-\sqrt{x}+1 }=\frac{\sqrt{x}+1}{(x+1)-\sqrt{x}}\\\\=\frac{(\sqrt{x}+1)([x+1]+\sqrt{x})}{([x+1]-\sqrt{x})+([x+1)+\sqrt{x}])}\\\\=\frac{\sqrt{x}*x+\sqrt{x}*1+\sqrt{x}*\sqrt{x}+1*x+1*1+1*\sqrt{x}}{(x+1)^{2}-(\sqrt{x})^{2}}\\\\\\=\frac{x\sqrt{x}+\sqrt{x}+x+1+x+\sqrt{x}}{x^{2}+2x+1-x}\\\\=\frac{x\sqrt{x}+2\sqrt{x}+2x+1}{x^{2}+x+1}\\\\$