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vampirchik [111]
4 years ago
7

15 points. Geometry question — HELP! See image.

Mathematics
2 answers:
AURORKA [14]4 years ago
8 0

Let point Q = (4,y)

√[ (4-0)^2 + (y-0)^2 ] = √[ (6-0)^2 + (0-0)^2 ]

Square both side

(4-0)^2 + (y-0)^2 = (6-0)^2 + (0-0)^2

4^2 + y^2 = 6^2

16 + y^2 = 36

y^2 = 36-16

y^2 = 20

y= √20

y= 2√5

konstantin123 [22]4 years ago
5 0

Answer:

2√5

Step-by-step explanation:

On the graphic, you see point Q is roughly between 4 and 4.5 units on the Y-axis.

So, all we have to do is find a value similar to that in the answer choices.  So, let's look at the values:

2√5:  2 * 2.23 = 4.46... that's pretty much what we're looking for.

4√2: 4 * 1.41 = 6.4.  Way too big.

2√13: 2 * 3.6 = 7.2, way too big.

8√2: We know that will necessary be way bigger than 4.5, so let's not even evaluate it.

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Step-by-step explanation:

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Jeannine needs to decide what size to make a rectangular
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Answer:

Total number of possible combinations are 6

Length   width

23 dm     2m

21 dm       4 dm

19 dm       6 dm

17 dm         8 dm

15 dm         10 dm

13 dm          12 dm

Step-by-step explanation:

We are given that

Perimeter of rectangular garden=50 dm

Width is  even number.

Length is always longer than or equal to width.

Let length of rectangular garden=x

Width of  rectangular garden=y

We have to find the possible  number of combinations .

Perimeter of rectangular garden=2(x+y)

2(x+y)=50

x+y=50/2

x+y=25

If y=2 dm

x=25-2=23 dm

If y=4 dm

x=25-4=21 dm

If y=6 dm

x=25-6=19 dm

If y=8 dm

x=25-8=17 dm

If y=10 dm

x=25-10=15 dm

If y=12 dm

x=25-12=13 dm

If y=14 dm

x=25-14=11 dm

x<y

It is  not possible

Then, possible combinations are 6

Length   width

23 dm     2m

21 dm       4 dm

19 dm       6 dm

17 dm         8 dm

15 dm         10 dm

13 dm          12 dm

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3 years ago
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Answer:

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Step-by-step explanation:


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