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Marizza181 [45]
3 years ago
6

Helppp pleaseeee I really need help

Mathematics
2 answers:
Naya [18.7K]3 years ago
5 0

Answer:

Step-by-step explanation:

S

Talja [164]3 years ago
4 0

Step-by-step explanation:

=  \frac{(2c {}^{2} + c - 2) }{(c + 1)}  \\ rationalise \: the \: denominator \\  =  \frac{(2 {c}^{2}  + c - 2)(c  -  1)}{(c + 1)(c - 1)}  \\  =  \frac{(2 {c}^{3}  - 2 {c}^{2} +  {c}^{2}  - c - 2c + 2) }{( {c}^{2}  -  {1}^{2} )}  \\   = \frac{(2 {c}^{3}  -  {c}^{2} - 3c + 2 )}{( {c}^{2} - 1) }

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What is √101.6064 in to 1 decimal place and in standard form?​<br>NEED ASAP
Dimas [21]

Note that

10² = 100

0.08² = 0.0064

and

101.6064 = 100 + 1.6 + 0.0064

It also happens that

1.6 = 2 • 10 • 0.08

which means

101.6064 = 100 + 1.6 + 0.0064

101.6064 = 10² + 2 • 10 • 0.08 + 0.08²

101.6064 = (10 + 0.08)²

101.6064 = 10.08²

which means

√101.6064 = 10.08

which, to one decimal place, is approximately 10.1.

3 0
2 years ago
2x - y = 8 <br> x - 4y = -3
mylen [45]

Answer:

X = 5

Y = 2

Step-by-step explanation:

y=2x-8

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x=5 -> y=2x-8 -> y=2(5)-8=2

7 0
3 years ago
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2/3 to 3/2 in simplest form
Rainbow [258]

Answer:

1 whole or 6/6

Step-by-step explanation:

3 0
3 years ago
assume that 70% of teenagers who go to take the written drivers license test have studied for the test. Of those who study for t
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P = \frac{P(pass AND not study)}{P(pass AND study) + P(pass AND not study)}  \\  \\  P = \frac{(.6)(.3)}{(.95)(.7) + (.6)(.3)} \\  \\  P = 0.213
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3 years ago
Oprah looks at this histogram of a distribution with a mean of 6.7 grams
Olin [163]

Answer:

68% of  the data is between 5.7 and 7.7 grams.

Step-by-step explanation:

According to the empirical rule for a normal distribution, 68% of data falls within one standard deviation, 95% of data falls within two standard deviation and 99.7% of data falls within three standard deviation.

Given that:

mean (μ) = 6.7 grams, standard deviation (σ) = 1 gram.

From the empirical rule:

68% of  the data is between one standard deviation i.e μ ± σ = 6.7 ± 1 = 5.7, 7.7

Therefore 68% of  the data is between 5.7 and 7.7 grams.

3 0
3 years ago
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