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Marizza181 [45]
3 years ago
6

Helppp pleaseeee I really need help

Mathematics
2 answers:
Naya [18.7K]3 years ago
5 0

Answer:

Step-by-step explanation:

S

Talja [164]3 years ago
4 0

Step-by-step explanation:

=  \frac{(2c {}^{2} + c - 2) }{(c + 1)}  \\ rationalise \: the \: denominator \\  =  \frac{(2 {c}^{2}  + c - 2)(c  -  1)}{(c + 1)(c - 1)}  \\  =  \frac{(2 {c}^{3}  - 2 {c}^{2} +  {c}^{2}  - c - 2c + 2) }{( {c}^{2}  -  {1}^{2} )}  \\   = \frac{(2 {c}^{3}  -  {c}^{2} - 3c + 2 )}{( {c}^{2} - 1) }

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I can’t figure out the solution I think it is y < -10
Olenka [21]

Hey there!

  • <em>With negatives (-) you have to switch your symbol to the other way</em>
  • \bold{\frac{y}{-2}\leq5}
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  • \bold{Cancel \ out:2\times\frac{-1}{2}y \ because \ it \ equal \ 1}
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  • \bold{-2\times5=-10}
  • \boxed{\boxed{\bold{Answer:y\geq-10}}}\checkmark

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Answer:

Step-by-step explanation:

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