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Juliette [100K]
4 years ago
12

Inverse Function In Exercise,analytically show that the functions are inverse functions.Then use the graphing utility to show th

is graphically.
f(x) = e^x/3
g(x) = Inx^3

Mathematics
1 answer:
DanielleElmas [232]4 years ago
8 0

Answer:

g^{-1}(x)=f(x)=e^{\frac{x}{3}}

Step-by-step explanation:

We have been given two functions as g(x)=\text{ln}(x^3) and f(x)=e^{\frac{x}{3}}. We are asked to show that both functions are inverse of each other algebraically and graphically.

Let us find inverse function of g(x)=\text{ln}(x^3) as:

y=\text{ln}(x^3)

Interchange x and y values:

x=\text{ln}(y^3)

Using log property \text{ln}(a^b)=b\cdot \text{ln}(a), we will get:

x=3\cdot \text{ln}(y)

\frac{x}{3}=\frac{3\cdot \text{ln}(y)}{3}

\frac{x}{3}=\text{ln}(y)

Using log definition; If \text{log}_a(b)=c, then b=a^c, we will get:

y=e^{\frac{x}{3}}

g^{-1}(x)=e^{\frac{x}{3}}

Therefore, we can see that function f(x)=e^{\frac{x}{3}} is inverse of function g(x)=\text{ln}(x^3).

We can see that both functions are symmetric about line y=x, therefore, both functions are inverse of each other.  

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To compute a student's Grade Point Average (GPA) for a term, the student's grades for each course are weighted by the number of
tia_tia [17]

Answer:

2.89, rounded to the nearest hundredth

Step-by-step explanation:

Given that GPA is weighted by credits, we must first multiply each grade by its credit amount and sum those up to weigh the credits. Then, we divide by the total amount of credits to get the GPA per credit.

So, we start with math,

3.7 *5 + 1.8 *3 + 2.8 * 5 + 2.8 * 4 = 49.1 as the total GPA weighted per credit.

Then, to find the average per credit, we divide by the total amount of credits, which is 5 + 3 + 5 + 4 = 17.

Our answer is 49.1/17 = 2.89, rounded to the nearest hundredth

4 0
3 years ago
-4(8r+3) pls answer
luda_lava [24]
<h3>given:</h3>

- 4(8r + 3)

<h3>solution:</h3>

- 4(8r + 3)

=  - 32r - 12

7 0
2 years ago
Read 2 more answers
What are the x-coordinates for the maximum points in the function f(x) = 4 cos(2x − π) from x = 0 to x = 2π? (1 point) a x = 3 p
Ratling [72]

x-coordinates for the maximum points in any  function  f(x) by f'(x) =0 would be  x = π/2 and x= 3π/2.

<h3>How to obtain the maximum value of a function?</h3>

To find the maximum of a continuous and twice differentiable function f(x), we can firstly differentiate it with respect to x and equating it to 0 will give us critical points.

we want to find x-coordinates for the maximum points in any  function  f(x) by f'(x) =0

Given f(x)= 4cos(2x -π)

f'(x) = 0\\- 4sin(2x -\pi ) =0\\\\sin (2x -\pi ) =0 \\2x -\pi  = k\pi ...  k in Z

In general  x=(k+1)\pi /2

from x = 0 to x = 2π :

when k =0  then  x = π/2

when k =1  then x= π

when k =2  then x= 3π/2

when k =3  then x=2π

Thus, X-coordinates of maximum points are  x = π/2 and x= 3π/2

Learn more about maximum of a function here:

brainly.com/question/13333267

#SPJ4

4 0
2 years ago
Plz help have to turn in today
oee [108]

Answer:

Function 2

Step-by-step explanation:

slope of Function 1 is 5/8

slope of Function 2 is 3/4, or 6/8

4 0
3 years ago
Simplify (7x) - (-2x).<br> O 5x<br> 0 -5x<br> O 9x<br> 0-9x<br> NEXT QUESTION<br> 2<br> ASK FOR UEL
marysya [2.9K]

Answer:

9x

Step-by-step explanation:

Since you are subtracting a negative from a positive you would get 9

3 0
4 years ago
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