So your question is how pieces are there?? If it is:
Its 2 pieces plus a 0.36m leftover
Answer:
Required probability equals 0.18%
Step-by-step explanation:
The probability that the primary and one auxiliary computer fails equals
1) Probability that A and B fails
2)Probability that A and C fails
Thus required probability equals

7 hours and 20 min, hope this helps mark me the brainliest
Here’s the prime numbers on one dice: 2 3 5, so 3/6. If you have two die then your answer is 6/12. You have a 50 percent chance of not rolling prime numbers on both.