Answer:
The space needle is 62.95 m tall.
Step-by-step explanation:
Given that,
The height of the shadow, h = 67 m
The angle of elevation from the tip of the shadow to the top of the Space Needle is 70°.
We need to find the height of the space needle.
The shadow of space needle is hypotenuse of right angled triangle. Let the height of the space needle is x m. Using trigonometry,
So, the space needle is 62.95 m tall.
2x-25=x+5 move your “x” on the right side to the left side but to move it you need to switch the sign to cancel it out on the right. That ends up giving you x-25=5. You want X by itself so you move over your “25” but also change the sign. Giving you x=30
To find your y you set the equation to 0. 9y+28=0. You want Y by itself, so you want to move the 28 over first. Switch the sign which gives you 9y=-28. To get y alone divide by 9. 28/9 = 3.1(repeating 1)
I believe the area of that polygon is 473 square feet because to find the area of the odd corner you have to look at the differences between the different side lengths, so 2*5=10 and then you have to divide 10 by 2 because only half of that corner is there.
The figures appear to be congruent to me, I simply counted the units that each of the bases had and also counted how far out the points went and got the same numbers.