Answer:
D. x = 10, m<TRS = 60°
Step-by-step explanation:
m<QRS = 122° (given)
m<QRT = (7x - 8)° (given)
m<TRS = (6x)° (given)
m<QRT + m<TRS = m<QRS (angle addition postulate)
(7x - 8)° + (6x)° = 122° (substitution)
Solve for x
7x - 8 + 6x = 122
Add like terms
13x - 8 = 122
13x = 122 + 8
13x = 130
x = 130/13
x = 10
✔️m<TRS = (6x)°
Plug in the value of x
m<TRS = (6*10)° = 60°
The vertex is (-1.5, -6.75). So the x-coordinate is -1.5. Hope this helps and if so please leave a good rating and thanks. I really appreciate it. Have a nice day!
Sent a picture of the solution to the problem (s).
The answer is 45.9 you Add it
(16xy + xy) + (4x) + (3y) + (-13 + 21)
17xy + 4x + 3y + 8