In the C programming language, you can't determine the array size from the parameter, so you have to pass it in as an extra parameter. The solution could be:
#include <stdio.h>
void swaparrayends(int arr[], int nrElements)
{
int temp = arr[0];
arr[0] = arr[nrElements - 1];
arr[nrElements - 1] = temp;
}
void main()
{
int i;
int myArray[] = { 1,2,3,4,5 };
int nrElements = sizeof(myArray) / sizeof(myArray[0]);
swaparrayends(myArray, nrElements);
for (i = 0; i < nrElements; i++)
{
printf("%d ", myArray[i]);
}
getchar();
}
In higher languages like C# it becomes much simpler:
static void Main(string[] args)
{
int[] myArray = {1, 2, 3, 4, 5};
swaparrayends(myArray);
foreach (var el in myArray)
{
Console.Write(el + " ");
}
Console.ReadLine();
}
static void swaparrayends(int[] arr)
{
int temp = arr[0];
arr[0] = arr.Last();
arr[arr.Length - 1] = temp;
}
Answer:
if(y==10)
{
x=0; // assigning 0 to x if y equals 10.
}
else
{
x=1; // assigning 1 to x otherwise.
}
Explanation:
In the if statement i have used equal operator == which returns true if value to it's right is equal to value to it's left otherwise false.By using this operator checking value of y and if it is 10 assigning 0 to x and if it is false assigning 1 to x.
Answer:
my dog chewed up the couch
Explanation:
Answer:
A
Explanation:
Option A is not true because a Boolean variable type can hold one of two values only that is (true/True or false/False).
All the other options given in the question are correct because
- A variable declaration refers to specifying its type and name
- If string variables are assigned a numeric values which is legal provided the values are enclosed in quaotes( " "), trying to carryout a mathematical operation like addition will result in string concatenation.
- The Variable name I_Love_to_eat_pizza is legal because it contains no special characters, doesn't start with a number and its not a reserved word in any language
