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butalik [34]
3 years ago
10

How long will the bus take to travel 300km, if it averages 60km/h?

Mathematics
1 answer:
prisoha [69]3 years ago
3 0

Answer:

5 hours.

Step-by-step explanation:

5 hours * 60km = 300km in 5 hours.

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The question is on the picture i need the full answer to both
Archy [21]

Answer:

Sorry don't know the answer

6 0
2 years ago
Read 2 more answers
The coordinate of the vertices for square CDEF translated 3 units right and 4 units up if the vertices are C(-3,1), D(1,5), E(5,
ELEN [110]
The statement is false because not all the corresponding point have been translated correctly from the original.

Here are the correct answers:

C: (-3, 1) to (0,5). CORRECT!
D: (1,5) to (4, 9) INCORRECT IN THE CHOICE
E: (5, 1) to (8, 5) INCORRECT IN THE CHOICE
F: (1, -3) to (4, 1) INCORRECT IN THE CHOICE
7 0
3 years ago
If the temperature is dropping at a rate of 2° per hour how many hours will it take to drop 15°
Tju [1.3M]

Answer:

7 1/2

Step-by-step explanation:

If it drops 2 per hour, and you need it to drop 15, divide 15 by 2 and you’ll get 7.5 or 7 1/2

5 0
3 years ago
4.) v = 3k<br>Solve for t​
qaws [65]
The whole thing flips around and ends up being t = 3k/?
7 0
3 years ago
If Susie is late for school one particular day of the week, the probability she arrives on time the next day is 0.8. If she arri
Andre45 [30]

Answer:

0.273 = 27.3% probability that she was late on Thursday.

Step-by-step explanation:

On time on Monday, late on Thursday:

Possible outcomes (tuesday-wednesday-thursday).

on time(0.7 probability) - on time(0.7 probability) - late(0.3 probability)

on time(0.7 probability) - late(0.3 probability) - late(0.2 probability)

late(0.3 probability) - on time(0.8 probability) - late(0.3 probability)

late(0.3 probability) - late(0.2 probability) - late(0.2 probability).

What is the probability she was late on Thursday?

Sum of these four outcomes. So

p = 0.7*0.7*0.3 + 0.7*0.3*0.2 + 0.3*0.8*0.3+0.3*0.2*0.2 = 0.273

0.273 = 27.3% probability that she was late on Thursday.

4 0
3 years ago
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