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iris [78.8K]
3 years ago
5

Five hundred yards of fence is to be used to enclose a rectangular area next to a straight river. The river bank acts as one sid

e of the rectangle, and the fence is used to make the other three sides of the rectangle. Suppose the width w in yards of the rectangle is along the river bank.
Mathematics
1 answer:
fenix001 [56]3 years ago
3 0

Answer:

the requirements are missing:

  1. express the height of the rectangle in terms of w
  2. express the area of the rectangle in terms of w

1) the height of the rectangle is:

w + h + h + w = 500 + w

2w + 2h = 500 + w

2h = 500 + w - 2w = 500 - w

h = (500 - w) / 2 = 250 - 0.5w

2) the are of the rectangle is:

w x h = w x (250 - 0.5w) = 250w - 0.5w²

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Step-by-step explanation:

The simple addition has to be done to solve the given problem

Given

total faxes = 4

Time for fax 1: t_1 = 14\ sec

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The total time t will be:

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3 years ago
Use integration by parts to find the integrals in Exercise.<br> x^3 ln x dx.
34kurt

Answer:

\frac{\text{ln}(x)x^4}{4}-\frac{x^4}{16}+C.

Step-by-step explanation:

We have been given an indefinite integral \int \:x^3\:ln\:x\:dx. We are asked to find the value of the integral using integration by parts.

\int\: u\text{dv}=uv-\int\: v\text{du}

Let u=\text{ln}(x), v'=x^3.

Now, we will find du and v as shown below:

\frac{du}{dx}=\frac{d}{dx}(\text{ln}(x))

\frac{du}{dx}=\frac{1}{x}

du=\frac{1}{x}dx

v=\frac{x^{3+1}}{3+1}=\frac{x^{4}}{4}

Upon substituting our values in integration by parts formula, we will get:

\int \:x^3\:\text{ln}\:(x)\:dx=\text{ln}(x)*\frac{x^4}{4}-\int\: \frac{x^4}{4}*\frac{1}{x}dx

\int \:x^3\:\text{ln}\:(x)\:dx=\frac{\text{ln}(x)x^4}{4}-\int\: \frac{x^3}{4}dx

\int \:x^3\:\text{ln}\:(x)\:dx=\frac{\text{ln}(x)x^4}{4}-\frac{1}{4}\int\: x^3dx

\int \:x^3\:\text{ln}\:(x)\:dx=\frac{\text{ln}(x)x^4}{4}-\frac{1}{4}*\frac{x^{3+1}}{3+1}+C

\int \:x^3\:\text{ln}\:(x)\:dx=\frac{\text{ln}(x)x^4}{4}-\frac{1}{4}*\frac{x^4}{4}+C

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Therefore, our required integral would be \frac{\text{ln}(x)x^4}{4}-\frac{x^4}{16}+C.

5 0
3 years ago
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