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Annette [7]
4 years ago
9

Lectura Read about Pedro, then indicate whether each statement is cierto or falso. Pedro es de Chile, pero (but) sus padres son

argentinos. Muchos de sus parientes viven en Chile. La familia de Pedro es muy grande. Su madre tiene cuatro hermanas y un hermano. Su padre tiene tres hermanos. Pedro estudia en la escuela y su materia favorita es geografía. Él no tiene novia, pero tiene muchas amigas en la clase. 1. Los padres de Pedro son argentinos. cierto falso 2. Pedro no tiene parientes en Chile. cierto falso 3. La madre de Pedro tiene cinco hermanas. cierto falso 4. Pedro es artista. cierto falso 5. A Pedro le gusta la geografía. cierto falso 6. Pedro tiene una novia en la escuela. cierto falso
Spanish
2 answers:
omeli [17]4 years ago
4 0

Answer:

1. cierto

2.falso

3.falso

4.falso

5.cierto

Explanation:

miv72 [106K]4 years ago
4 0

1.True (cierto)

2.False (falso)

3.False (falso)

4.False (falso)

5.true (cierto)

6.False (falso)

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\green{{\hspace{50 pt}\above 1.2pt}\boldsymbol{\mathsf{Procedimiento}}{\hspace{50pt}\above 1.2pt}}

276. Para resolver los ejercicos igualaremos a una constante cada proporción.

\begin{gathered}\begin{array}{ccc}\\\hspace{80pt}\sf{\dfrac{m}{2}= \dfrac{n}{6} = \blue{\boldsymbol{\sf{k}}}}\\\\\boldsymbol{\bigcirc \kern-11.5pt \blacktriangleright} \:\: \sf{\dfrac{m}{2} = k}&\hspace{-20pt}\boldsymbol{\bigcirc \kern-11.5pt \blacktriangleright} \:\: \sf{\dfrac{n}{6} = k}\\\\\\\boxed{\sf{m=2k}}&\hspace{-20pt}\boxed{\sf{n=6k}}\end{array}\end{gathered}

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\begin{gathered}\begin{array}{c}\sf{m + n =12 }\\\\\sf{(2k)+(6k) = 12}\\\\\sf{8k = 12}\\\\\sf{k = \dfrac{\not\!\!12}{\not\!8}}\\\\\sf{k = \dfrac{3}{2}}\end{array}\end{gathered}

Reemplazamos "k" para determinar los valores de "m" y "n"

\begin{gathered}\begin{array}{cccccccc}\\\sf{m=2k }&&&&&&&\sf{n=6k }\\\\\sf{m= 2\left(\dfrac{3}{2}\right)}&&&&&&&\sf{n= 6\left(\dfrac{3}{2}\right)}\\\\\boxed{\boxed{\boldsymbol{\sf{m = 3}}}}&&&&&&&\boxed{\boxed{\boldsymbol{\sf{n = 9}}}}\end{array}\end{gathered}

277. Otra manera de resolver es despejando una variable de la siguiente manera

\begin{gathered}\begin{array}{c}\sf{\dfrac{8}{m}=\dfrac{12}{n}}\\\\\sf{n=\dfrac{12m}{8}}\\\\\sf{n=\dfrac{3m}{2}}\end{array}\end{gathered}

Reemplazamos "n"

\begin{gathered}\begin{array}{c}\sf{m+n = 35}\\\\\sf{m+\left(\dfrac{3m}{2}\right)=35}\\\\\sf{\dfrac{2m+3m}{2}=35}\\\\\sf{\dfrac{5m}{2}=35}\\\\\sf{5m=70}\\\\\sf{m=\dfrac{70}{5}}\\\\\boxed{\boxed{\boldsymbol{\sf{m=14}}}}\end{array}\end{gathered}

Para determinar "m" reemplazamos "n"

\begin{gathered}\begin{array}{c}\sf{n=\dfrac{3m}{2}}\\\\\sf{n=\dfrac{3(14)}{2}}\\\\\boxed{\boxed{\boldsymbol{\sf{n=21}}}}\end{array}\end{gathered}

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\begin{gathered}\begin{array}{c}\sf{\dfrac{10}{m}=\dfrac{15}{n}}\\\\\sf{n=\dfrac{15m}{10}}\\\\\sf{n=\dfrac{3m}{2}}\end{array}\end{gathered}

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\begin{gathered}\begin{array}{c}\sf{m+n = 48}\\\\\sf{m+\left(\dfrac{3m}{2}\right)=48}\\\\\sf{\dfrac{2m+3m}{2}=48}\\\\\sf{\dfrac{5m}{2}=48}\\\\\sf{5m=96}\\\\\sf{m=\dfrac{96}{5}}\\\\\boxed{\boxed{\boldsymbol{\sf{m=19.2}}}}\end{array}\end{gathered}

Para determinar "m" reemplazamos "n"

\begin{gathered}\begin{array}{c}\sf{n=\dfrac{3m}{2}}\\\\\sf{n=\dfrac{3(19.2)}{2}}\\\\\boxed{\boxed{\boldsymbol{\sf{n=28.8}}}}\end{array}\end{gathered}

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