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Phoenix [80]
3 years ago
9

Let hh be the set of all points in the second quadrant in the plane v=ℝ2v=r2. that is, h={(x,y)∣x≤0,y≥0}h={(x,y)∣x≤0,y≥0}. is hh

a subspace of the vector space vv?
Mathematics
1 answer:
BaLLatris [955]3 years ago
7 0
No, H is not a subspace of V. A simple counter-example to the contrary: let h\in H with h=(-1,0). However, scaling by -1 gives the vector -h=(1,0) and -h\not\in H.
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Comment
I'm going to take a guess at this and say what you meant is  2401 = 7^(6 - 2x)

Step One
Find out the power of 7 that will equal 2401. 
You could do it like this.
7^y = 2401 and just guess at some values.

y      7^y
1      7
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3      7 * 7 * 7 = 343
4      7 * 7 * 7 * 7 = 2401  So the answer is 4

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Step 2 
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4 - 6 = - 2x 
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-2/-2 = x
x = 1 <<<<<<<<<<<<<answer

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