(c)*(d)=8*30+8*4=8*34,=>
c=8
d=34
a+b>a-b, =>a+b=d, a-b=c; =>
{a+b=34
{a-b=8, =>a=b+8 ;
(b+8)+b=34
2b=34-8
b=13
a=13+8=21
Answer: a=21; b=13; c=8; d=34.
Answer:
Step-by-step explanation:
Answer:
Option D) Yes, he made an error. Because he was seeking the probability that his home runs traveled at least 385 feet, he looked up −0.46 and failed to subtract the probability from 1. The correct probability is 0.6772.
Step-by-step explanation:
We are given that Evan's home run hitting distance is normally distributed with a mean of 398 feet and a standard deviation of 28 feet i.e. = 398 feet and = 28 feet.
Also, He wanted to find the probability that his home runs traveled at least 385 feet. He calculated the z-score to be −0.46 and looked up the probability on the Standard Normal Probabilities table. He found that the table stated his probability as 0.3228 .
The probability he stated is wrong because as we know that probability that his home runs traveled at least 385 feet is given by P(X >= 385 feet) ;
where, X = home run is being hit
Z = ~ N(0,1)
P(X >= 385) = P( >= ) = P(Z >= -0.46) = P(Z <= 0.46) = 0.6772.
When looking at the z table we find that at 0.46 critical value of x, the probability area is 0.6772 .
A because just multiply 1/4 by 16 and u get 4
9514 1404 393
Answer:
p = 3/4n +3
Step-by-step explanation:
Expressing the given equation in terms of powers of 3, we have ...
(27^(n+3))/(81^(p-1)) = 3
(3^3)^(n+3)/(3^4)^(p-1) = 3^1 . . . . as powers of 3
3(n +3) -4(p -1) = 1 . . . . . . . . . . . . log base 3 (or, equate exponents)
3n +9 -4p +4 = 1 . . . . . . . . . . . . . eliminate parentheses
3n +12 = 4p . . . . . . . . . . . . . . . . add 4p -1
p = 3/4n +3 . . . . . . . . . . divide by 4