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rosijanka [135]
3 years ago
15

Could somebody help me with this please?

Mathematics
1 answer:
katrin [286]3 years ago
8 0

Answer:

1) x ≅ 51.34°

2) y ≅ 38.66°

Step-by-step explanation:

In the right triangle given in the figure

∵ The triangle has a right angle

∴ Angles x and y are acute angles and the sum of their measures is 90°

→ By using the trigonometry function tan

∵ tan(x) = opposite side to x/adjacent side to x

∵ The opposite side to x = 10

∵ The adjacent side to x = 8

→ Substitute them in the rule above

∴ tan(x) = \frac{10}{8} = \frac{5}{4}

→ Use the inverse of tan to find x

∵ x = tan^{-1}(\frac{5}{4})

∴ x = 51.34019175

∴ x ≅ 51.34°

∵ x + y = 90°

∴ 51.34 + y = 90

→ Subtract 51.34 from both sides

∴ y ≅ 38.66°

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Assignment: \bold{Simplify \ Equation: \ 7\left(3\sqrt{2}x\right)-3\left(3\sqrt{16}x\right)-3\left(3\sqrt{8}x\right)}

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Answer: \boxed{\bold{3\sqrt{2}x-36x}}

<><><><><><><>

Explanation: \downarrow\downarrow\downarrow

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[ Step One ] Remove Parenthesis (a) = a

\bold{7\cdot \:3\sqrt{2}x-3\cdot \:3\sqrt{16}x-3\cdot \:3\sqrt{8}x}

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\bold{\rightarrow Mordancy \leftarrow}

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3 years ago
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Answer:

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Step-by-step explanation:

The diagram illustrating the question is shown on the first uploaded image

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   The bearing from B to  C is  \theta_{BC} =  N 28.7E

   The bearing from B to  A is  \theta_{BA} =  N 60.7E

   The  bearing from A to  B is   \theta_{AB} =  S60.7W

    The  bearing from A to  C is   \theta_{AC} =  S79.1W

Generally from the diagram

     \theta_A  =  180 - 60.7 -79.1

=>  \theta_A  =  40.2 ^o

Also

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=>   \theta_C  =  180 - (40.2  + 32 )

=>   \theta_C  =  107.8 ^o

Generally according to Sine Rule

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