What is the exact product of 379 and 8

There was no actually pyramid for these questions it tells you the measurements in the problem though. please help me

Nimfa-mama [501]

V=448 in^3
l=8 in
w=12
h=?
V=l•w•h/3
448=8•12•h/3 multiply both sides by 3
3•448=96•h
1344=96•h
h=1344/96
h=14 in

V=l•w•h/3
h=4in
l=3in
w=2.5 in
V=?
V=4•3•2.5/3
V=30/3
V=10 in^3

3 0

3 years ago

If a radioactive isotope has a half-life of 6 hours and 12 milligrams is initially present, how much will

Serhud [2]

Answer:0.75 milligrams will be present in 24 hours

Step-by-step explanation:

Step 1

The formula for radioactive decay can be written as

N(t)=No (1/2)^(t/t 1/2)

where

No= The amount of the radioactive substance at time=0=milligrams

t 1/2= the half-life= 6 hours

t=24 hours

N(t) = the amount at time t

Step 2--- Solving

N(t)=No (1/2)^(t/t 1/2)

=N(t)=12 x ( 1/2) ^ (24/6)

= 12 x (1/2) ^4

= 12 x 0.0625

= 0.75 milligrams

3 0

2 years ago

Giving 25 points for whoever answers it with a complete explanation .. ASAP

MAXImum [283]

No, it is not a function.
Since all the lines have been drawn in the grid line do not have any connection between them even a point in common.
I hope this has been useful for you.

8 0

2 years ago

Read 2 more answers

Write an inequality

Fudgin [204]

Answer:60

Step-by-step explanation:

5 0

3 years ago

This is a geometry question, i need something quickly :)

Marysya12 [62]

Answer:

hope it helps mark me brainlieast!

Step-by-step explanation:

For triangle ABC with sides a,b,c labeled in the usual way,

c2=a2+b2−2abcosC

We can easily solve for angle C .

2abcosC=a2+b2−c2

cosC=a2+b2−c22ab

C=arccosa2+b2−c22ab

That’s the formula for getting the angle of a triangle from its sides.

The Law of Cosines has no exceptions and ambiguities, unlike many other trig formulas. Each possible value for a cosine maps uniquely to a triangle angle, and vice versa, a true bijection between cosines and triangle angles. Increasing cosines corresponds to smaller angles.

−1≤cosC≤1

0∘≤C≤180∘

We needed to include the degenerate triangle angles, 0∘ and 180∘, among the triangle angles to capture the full range of the cosine. Degenerate triangles aren’t triangles, but they do correspond to a valid configuration of three points, namely three collinear points.

The Law of Cosines, together with sin2θ+cos2θ=1 , is all we need to derive most of trigonometry. C=90∘ gives the Pythagorean Theorem; C=0 and C=180∘ give the foundational but often unnamed Segment Addition Theorem, and the Law of Sines is in there as well, which I’ll leave for you to find, just a few steps from cosC= … above. (Hint: the Law of Cosines applies to all three angles in a triangle.)

The Triangle Angle Sum Theorem, A+B+C=180∘ , is a bit hard to tease out. Substituting the Law of Sines into the Law of Cosines we get the very cool

2sinAsinBcosC=sin2A+sin2B−sin2C

Showing that’s the same as A+B+C=180∘ is a challenge I’ll leave for you.

In Rational Trigonometry instead of angle we use spreads, squared sines, and the squared form of the formula we just found is the Triple Spread Formula,

4sin2Asin2B(1−sin2C)=(sin2A+sin2B−sin2C)2

true precisely when ±A±B±C=180∘k , integer k, for some k and combination of signs.

This is written in RT in an inverted notation, for triangle abc with vertices little a,b,c which we conflate with spreads a,b,c,

(a+b−c)2=4ab(1−c)

Very tidy. It’s an often challenging third degree equation to find the spreads corresponding to angles that add to 180∘ or zero, but it’s a whole lot cleaner than the trip through the transcendental tunnel and back, which almost inevitably forces approximation.

6 0

2 years ago