The answer is √58 = 7.62
So, if you draw this down, you will see that the direct distance is hypotenuse c of a right triangle which sides are 3 blocks (1 south and 2 north) and 7 blocks (4 west and 3 east).
Use the Pythagorean theorem:
c² = a² + b²
a = 3
b = 7
c² = 3² + 7²
c² = 9 + 49
c² = 58
c = √58
c = 7.62
Answer:
2 4/20
Step-by-step explanation:
4 × 2 = 8
8 + 3 = 11
11/4 × 4/5
11 × 4 = 44
4×5= 20
44/20
Simplified is
2 4/20
Answer:
1-i and -1+i
Step-by-step explanation:
We are to find the square roots of 
. First, convert from Cartesian to polar form:
Next, use the formula ![\displaystyle \sqrt[n]{r}\biggr[\cis\biggr(\frac{\theta+2\pi k}{n}\biggr)\biggr]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csqrt%5Bn%5D%7Br%7D%5Cbiggr%5B%5Ccis%5Cbiggr%28%5Cfrac%7B%5Ctheta%2B2%5Cpi%20k%7D%7Bn%7D%5Cbiggr%29%5Cbiggr%5D)
where 
to find the square roots:
<u>When k=1</u>
<u />![\displaystyle \sqrt[2]{2}\biggr[cis\biggr(\frac{\frac{3\pi}{2}+2\pi(1)}{2}\biggr)\biggr]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csqrt%5B2%5D%7B2%7D%5Cbiggr%5Bcis%5Cbiggr%28%5Cfrac%7B%5Cfrac%7B3%5Cpi%7D%7B2%7D%2B2%5Cpi%281%29%7D%7B2%7D%5Cbiggr%29%5Cbiggr%5D)
![\displaystyle \sqrt{2}\biggr[cis\biggr(\frac{3\pi}{4}+\pi\biggr)\biggr]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csqrt%7B2%7D%5Cbiggr%5Bcis%5Cbiggr%28%5Cfrac%7B3%5Cpi%7D%7B4%7D%2B%5Cpi%5Cbiggr%29%5Cbiggr%5D)
<u>When k=0</u>
<u />![\displaystyle \sqrt[2]{2}\biggr[cis\biggr(\frac{\frac{3\pi}{2}+2\pi(0)}{2}\biggr)\biggr]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csqrt%5B2%5D%7B2%7D%5Cbiggr%5Bcis%5Cbiggr%28%5Cfrac%7B%5Cfrac%7B3%5Cpi%7D%7B2%7D%2B2%5Cpi%280%29%7D%7B2%7D%5Cbiggr%29%5Cbiggr%5D)
Thus, the square roots of -2i are 1-i and -1+i
Answer:
A is equal to 3
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4 + 5 = 9
180 ÷ 9 = 20
Sand = 20×4 = 80
Cement = 20×5 = 100
