Answer:
4618.14
or 4618
Step-by-step explanation:
From T.S.A = 2
rh + 2
where T.S.A = 1628
1628 = 2rh + 2
1628 = ( rh + ) 2
by dividing both side by 2
= rh +
259.10 = rh +
rh = 259.10 -
h = 
<u> </u>(1)
From Radius + Height = 37
r + h = 37 <u> </u>(2)
by substituting eqn 1 into 2
r + = 37
by multiplying r to both side
+ 259.10 - = 37r
259.10 = 37r
r = 
r = 7.00 ≅ 7
From Eqn 2
r + h = 37
7 + h = 37
h = 37 - 7
h = 30
so Volume of a cylinder = 
V = * 
* 30
V = 4618.14 ≅ 4618
Answer:
Claim 2
Step-by-step explanation:
The Inscribed Angle Theorem* tells you ...
... ∠RPQ = 1/2·∠ROQ
The multiplication property of equality tells you that multiplying both sides of this equation by 2 does not change the equality relationship.
... 2·∠RPQ = ∠ROQ
The symmetric property of equality says you can rearrange this to ...
... ∠ROQ = 2·∠RPQ . . . . the measure of ∠ROQ is twice the measure of ∠RPQ
_____
* You can prove the Inscribed Angle Theorem by drawing diameter POX and considering the relationship of angles XOQ and OPQ. The same consideration should be applied to angles XOR and OPR. In each case, you find the former is twice the latter, so the sum of angles XOR and XOQ will be twice the sum of angles OPR and OPQ. That is, angle ROQ is twice angle RPQ.
You can get to the required relationship by considering the sum of angles in a triangle and the sum of linear angles. As a shortcut, you can use the fact that an external angle is the sum of opposite internal angles of a triangle. Of course, triangles OPQ and OPR are both isosceles.
<span>560 = 14a+16b
560-14a=16b
b=(560-14a)/16
b=-7/8a+35
Answer is B</span>
So Jenson has 256 beads + 67 beads = 323 beads - 157 beads for the <span>necklaces = </span> 166 beads divided by 8 beads per bracelet = 20 bracelets with the remainder of 6 beads.
Answer:
first option
Step-by-step explanation:
