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yanalaym [24]
4 years ago
9

What are two examples of an accelerating object ?

Physics
1 answer:
givi [52]4 years ago
3 0

-- Steven is in his car, rolling slowly but with his foot on the gas and speeding up.

-- Sharon is in her car, rolling fastly but with her foot on the brake and slowing down.

-- Josh is in his car, keeping at a steady 20 miles per hour as he turns the corner.

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The age of the universe is thought to be about 14 billion years. Assuming two significant figures, write this in powers of ten i
ira [324]
A ) 14 billion years =  14,000,000,000
1.4 * 10^{10}
b ) 1 year = 365 · 24 · 3,600 = 31,536 · 10³ 
1.4 * 10 ^{10}*3.1536 * 10^{7}  =4.4 * 10 ^{17}

6 0
4 years ago
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You stand on a straight desert road at night and observe a vehicle approaching. This vehicle is equipped with two small headligh
zhuklara [117]

Complete Question

You stand on a straight desert road at night and observe a vehicle approaching. This vehicle is equipped with two small headlights that are 0.681 m apart. At what distance, in kilometres, are you marginally able to discern that there are two headlights rather than a single light source?Take the wavelength of the light to be 549 nm and your pupil diameter as 4.63 mm.  

Answer:

The distance is  z  = 4707.6 \ m

Explanation:

From the question we are told that

    The is distance between the headlight is d = 0.681 \ m

   The wavelength is  \lambda = 549 \ nm = 549 *10^{-9} \ m

    The  pupil diameter is  D  = 4.63 \ mm = 0.00463 \ m

Generally, we can mathematically evaluate the resolution of the eye as

            \theta  = \frac{1.22 *  \lambda }{D}

    substituting values

              \theta  = \frac{1.22 *  549 *10^{-9} }{0.00463}

              \theta  =  (1.45 *10^{-4} )^o

Now according to SOHCAHTOA rule  

         sin \theta  =  \frac{ d}{z}

Where z is  the distance at which the eye can discern the two head light

  given that the angle is very small sin \theta =  \theta

=>    \theta  =  \frac{ d}{z}

substituting values

     1.45*10^{-4}  =  \frac{ 0.681}{z}

=>   z  = \frac{0.681}{1.45 *10^{-4}}

=>    z  = 4707.6 \ m

   

6 0
4 years ago
What are some of the challenges that face wave energy production?
valentina_108 [34]

Answer:

One of the major obstacles with any wave resource study is lack of long-term ocean wave measurements inside the 100-meter-depth contour, where refraction effects result in spatially inhomogeneous wave parameters. Lack of data makes it difficult or impossible to mark the optimum locations for WECs.

Explanation:

4 0
3 years ago
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What is the mass of 5 m3 of cement of 3000 kg/m-3​
Scilla [17]

Answer:

It is 15000 Kgs.

4 0
3 years ago
Bella makes the 6.1m distance to her food bowl in 8.8 seconds what is her average velocity
storchak [24]
Bella’s average velocity is about 0.693 meters per second.

To find the average velocity, you must divide the distance by the change in time, which should look like v=d/t

Here is how you set up the equation-
v=6.1/8.8

Once you divide 6.1 meters by 8.8 seconds, you should get a number that looks like 0.69318182.... however, I just rounded it to 0.693 meters per second. You can round it to whatever you like.

Hope this helped! If you have any questions about what I mentioned in my answer or explanation, feel free to comment on my answer and I’ll try to get back to you!
8 0
3 years ago
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