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denis23 [38]
3 years ago
15

I need help with shifting functions

Mathematics
2 answers:
elixir [45]3 years ago
3 0

。☆✼★ ━━━━━━━━━━━━━━  ☾  

g(x) = h(x - 7) + 5

The plus 5 on the outside of the brackets represents the graph moving up by 5 units

The minus 7 on the inside of the brackets represents the graph moving right by 7 units.

Note: When it is on the inside of the brackets, you would do the opposite of what it suggests.

Normally, minus 7 would mean the graph shifts to the left, however, it means the opposite in this case.

Have A Nice Day ❤    

Stay Brainly! ヅ    

- Ally ✧    

。☆✼★ ━━━━━━━━━━━━━━  ☾

Dmitriy789 [7]3 years ago
3 0

g(x) = h (x - 7) + 5

Hope this helps!

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Find the value of x which satisfies the following equation.<br> log2(x−1)+log2(x+5)=4
weqwewe [10]

\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \: x = 3

____________________________________

\large \tt Solution  \: :

\qquad \tt \rightarrow \:  log_{2}(x - 1)  log_{2}(x + 5)  = 4

\qquad \tt \rightarrow \:  log_{2} \{(x - 1)(x + 5) \} = 4

[ log (x) + log (y) = log (xy) ]

\qquad \tt \rightarrow \: ( x - 1)(x + 5) =  {2}^{4}

\qquad \tt \rightarrow \:  {x}^{2}  + 5x - x - 5 =  16

\qquad \tt \rightarrow \:  {x}^{2}  + 4x - 5 - 16 = 0

\qquad \tt \rightarrow \:  {x}^{2}  + 4x -21 = 0

\qquad \tt \rightarrow \:  {x}^{2}  + 7x - 3x - 21 = 0

\qquad \tt \rightarrow \:  x(x + 7) - 3(x + 7) = 0

\qquad \tt \rightarrow \: (x + 7)(x - 3) = 0

\qquad \tt \rightarrow \: x =  - 7 \:  \: or \:  \: x = 3

The only possible value of x is 3, since we can't operate logarithm with a negative integer in it.

\qquad \tt \rightarrow \: x = 3

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

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2 years ago
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Answer:

16) b and 17) C

Step-by-step explanation:

8 0
3 years ago
How do you solve the problem -x-29=13+2x
serious [3.7K]
-x-29=13+2x
-29=13+3x
-42=3x
x=-14
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Need the (x) &amp; (y) value
Katen [24]

Answer:

x=0

y=6

Step-by-step explanation:

Two equations with two unknowns can be solved. Use the three steps given below.

In general you can save time if you use the simplest expression for step 1. You can choose either expression to start with x =.. or you can rewrite it, so it starts with y =...

FOLLOW THESE STEPS:

1. Rewrite the first expression so it starts with y =...

2. Then use that expression and substitute it in the other expression, to find the value for x.

3. Use that value found in step 2. and substitute it in the rewritten expssion you created in step 1. Solve this last expression and you'll get the value for y.

Step 1.

-6y + 11x = -36

-6y = -11x -36

multiply left and right of the = sign by -1

6y = 11x + 36

divide left and right of the = sign by 6

y = 11x/6 + 36/6

y = 11/6x + 6

Step 2.

-4 * ( y ) + 7x = -24

-4 * ( 11/6x + 6 ) + 7x = -24

( -44/6x - 24 ) + 7x = -24

-44/6x + 7x = -24 + 24

You can see immediately that ...x = 0

Just for fun of it ....

-44/6x + 42/6x = 24 - 24

(-44+42)/6x = 0

-2/6x = 0

-1/3x = 0

multiply left and right of the = sign by -3

3/3x = 0 * -3

x = 0

Step 3.

y = 11/6( x ) + 6. and substitute x = 0 gives:

y = 11/6( 0) + 6

y = 0 + 6

y = 6

3 0
2 years ago
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