Answer:
Ground the electrical equiptment so no power surges come through and fry the equiptment if there is a storm etc.
Explanation:
Answer:
#include<bits/stdc++.h>
using namespace std;
int main()
{
string st;
getline(cin,st);
int i=0;
while(i<st.length())
{
if(isupper(st[i]))
{
st.erase(st.begin()+i);
continue;
}
i++;
}
cout<<st<<endl;
return 0;
}
Explanation:
I have included the file bits/stdc++.h which include almost most of the header files necessary.
For taking the input as a string line getline is used.
For checking the upper case isupper() function is used. cctype header file contains this function.
For deleting the character erase function is used.
Pay attentions to what you are watching and or listening to.
Answer:
1.6KWh
Explanation:
La fórmula de la eficiencia del consumo energético es,
eficiencia = (salida / entrada) x 100
La eficiencia del aparato es = 70%
potencia en = 2,3 KWh
potencia de salida = vatios x (45 minutos / 60) veces en horas.
70 = (vatios(45/60) / 2,3 x 10 ^ 3) 100
0.7 = vatios(45/60) / 2,3 x 10 ^ 3 //dividir ambos lados por 100
1610 = vatios(0.75) //multiplica ambos lados por 2300
potencia de salida = vatios (0,75) = 1610/1000 = 1,6KWh
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