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3 years ago

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If leslie moves $10,000 of her money into an account that pays 8 percent compounded annually for 5 year(s), the amount of money

that will accumulate is

1 answer:

prohojiy [21]3 years ago

5 0

I gave you the number to multiply it by, in my answer
to the question you posted 13 minutes ago.

Get busy multiplying !

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Tanya has a garden with a trench around it. The garden is a rectangle with length 2.5m and width 2m. The trench and the garden t

Drupady [299]

Answer:

5.5m^2

the area of just the trench is 5.5 m^2

Step-by-step explanation:

The Area of trench only is the total area(trench and garden) minus the Area of garden

Area of trench only = total area(trench and garden) - Area of garden

Area = length × breadth

Substituting the given dimensions;

Total area = 3.5 × 3 = 10.5 m^2

Area of garden = 2.5×2 = 5 m^2

Area of trench only = 10.5 m^2 - 5 m^2

Area of trench only = 5.5m^2

the area of just the trench is 5.5 m^2

8 0

3 years ago

Read 2 more answers

Which story problem is solved using multiplication? Answer options with 5 options

galina1969 [7]

D is the answer because it says each and that’s a key word to understand that it’s multiplying

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3 years ago

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A mother has two children whose ages differ by 5 years. The sum of the squares of their ages is 97. The square of the mother's

svetoff [14.1K]

Answer:

41 years old.

Step-by-step explanation:

Let x represent age of younger child.

We have been given that a mother has two children whose ages differ by 5 years. So the age of older child would be $x+5$ .

The sum of the squares of their ages is 97. We can represent this information in an equation as:

$x^2+(x+5)^2=97$

Let us solve for x.

$x^2+x^2+10x+25=97$

$2x^2+10x+25-97=0$

$2x^2+10x-72=0$

Divide both sides by 2:

$x^2+5x-36=0$

$x^2+9x-4x-36=0$

$x(x+9)-4(x+9)=0$

$(x+9)(x-4)=0$

$(x+9)=0 ; (x-4)=0$

$x=-9 ; x=4$

Since age cannot be negative, therefore, age of younger child is 4 years.

Age of older child would be $x+5\Rightarrow4+5=9$

Therefore, the age of older child would be 9 years.

We have been given that the square of the mother's age can be found by writing the squares of the children's ages one after the other as a four-digit number.

Square of 4: $4^2=16$

Square of 9: $9^2=81$ .

Square of mother's age: $1681$

To find mother's age, we need to take positive square root of 1681 as:

$\sqrt{1681}=41$

Therefore, the mother is 41 years old.

4 0

3 years ago

Which one is a better deal?

saul85 [17]

12 pack is a better deal

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2 years ago

Which point would be a solution to the system of linear inequalities ?

brilliants [131]

Answer:

(12,-6)

Step-by-step explanation:

we have

$y\leq \frac{4}{3}x+5$ ----> inequality A

$y\geq -\frac{5}{2}x+5$ ---> inequality B

we know that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities (makes true both inequalities)

<u><em>Verify each point</em></u>

Substitute the value of x and the value of y of each ordered pair in the inequality A and in the inequality B

case 1) (0,-1)

Inequality A

$-1\leq \frac{4}{3}(0)+5$

$-1\leq5$ ----> is true

Inequality B

$-1\geq -\frac{5}{2}(0)+5$

$-1\geq 5$ ----> is not true

therefore

The ordered pair is not a solution of the system

case 2) (0,3)

Inequality A

$3\leq \frac{4}{3}(0)+5$

$3\leq5$ ----> is true

Inequality B

$3\geq -\frac{5}{2}(0)+5$

$3\geq 5$ ----> is not true

therefore

The ordered pair is not a solution of the system

case 3) (-6,-6)

Inequality A

$-6\leq \frac{4}{3}(-6)+5$

$-6\leq-3$ ----> is true

Inequality B

$-6\geq -\frac{5}{2}(-6)+5$

$-6\geq 20$ ----> is not true

therefore

The ordered pair is not a solution of the system

case 4) (12,-6)

Inequality A

$-6\leq \frac{4}{3}(12)+5$

$-6\leq21$ ----> is true

Inequality B

$-6\geq -\frac{5}{2}(12)+5$

$-6\geq -25$ ----> is true

therefore

The ordered pair is a solution of the system (makes true both inequalities)

8 0

3 years ago