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Dahasolnce [82]
4 years ago
14

Write the place vslue of 7in 67,689

Mathematics
1 answer:
Tems11 [23]4 years ago
8 0
The value of 7 can be wrote as

7,000 or seven thousand
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While traveling to Europe, Phelan exchanged 250 US dollars for euros. He spent 150 euros on his trip. After returning
yulyashka [42]

Answer:

44.70 US dollars

Step-by-step explanation:

euro left=(250/1.3687)-150=32.66(rounded to nearest cents

US dollars=32.66x1.3687

                =44.70US dollars

5 0
2 years ago
henry and 28 classmates go to the roller skating ring. each van can hold 11 students. if all of the vans are full except one, ho
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There is 6 people in the van that isn't full. I am counting. They are counting students. They are going to group them in 2 vans of 11 people and 1 van of 6 people.
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3 years ago
Need help please. Thank u
a_sh-v [17]
The answer is the third option choice
3 0
3 years ago
A rectangular restaurant kitchen is 24 meters long and 10 meters wide. what is its perimeter?​
scZoUnD [109]

Answer:

68

Step-by-step explanation:

24+24=48

                =68

10+10=20

8 0
3 years ago
Jaclyn plays singles for the varsity tennis team where she won the sudden death tie breaker point with a cross-court passing sho
podryga [215]

Answer:

Incomplete question

Complete question: Jaclyn plays singles for South's varsity tennis team. During the match against North, Jaclyn won the sudden death tiebreaker point with a cross-court passing shot. The 57.5-gram ball hit her racket with a northward velocity of 26.7 m/s. Upon impact with her 331-gram racket, the ball rebounded in the exact opposite direction (and along the same general trajectory) with a speed of 29.5 m/s.

a. Determine the pre-collision momentum of the ball.

b. Determine the post-collision momentum of the ball.

c. Determine the momentum change of the ball.

Answer:

A. 1.5353kgm/s

B. 1.6963kgm/s

C. 0.161kgm/s

Step-by-step explanation:

A. The pre-collision momentum of the ball = mass of ball × velocity of ball

Mass of ball = 57.5g = 0.0575kg

Velocity of ball = 26.7m/s

Pre-collision momentum of ball = 0.0575×26.7

= 1.5353kgm/s

B. Post collision momentum of the ball = mass of ball × velocity of ball after impact

Velocity of ball after impact = 29.5m/s

Post collision momentum of ball after impact = 0.0575×29.5

= 1.6963kgm/s

C. Momentum change of ball = momentum after impact - momentum before imlact

= 1.6963kgm/s - 1.5353kgm/s

= 0.161kgm/s

7 0
3 years ago
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