There's really no way to solve this problem apriori (unless you can use tools like lagrange polynomials to interpolate points), so I'll just tell you how to approach problems like this.
First of all, we may try to see if the dependence is linear: the input is always increased by 4 (4, 8, 12, 16,...) and the output increases by 2: (5, 7, 9, 11). So, the answer is yes.
Now that we know that these points lay on a line, we can conclude the exercise in several ways:
- We already know that the slope is 1/2 (4 units up in the x direction correspond to 2 units up in the y direction). So, we only need the y-intercept. If we go back one step, we can see that the next point would be (0, 3) (I decreased the x coordinate by 4 and the y coordinate by 2). So, the y intercept is 3, and the equation of the line is

- We can use the equation of the line passing through two points:

Plug in two points of your choice and you'll get the same answer.
Of course, as a third alternative, you could just have eyeballed the answer: the fact that x grows twice as fast as y could have hinted the x/2 part, and then you could have seen that y is always 3 more than half of x, again leading to y=x/2+3.
I think it’s what ever you have left after paying, I’m sorry if this is wrong.
Answer:
(2, - 1 ) and (5, 2 )
Step-by-step explanation:
y + 2 = (x - 3)² → (1)
y + 3 = x ( subtract 3 from both sides )
y = x - 3 → (2)
Substitute y = x - 3 into (1)
x - 3 + 2 = (x - 3)² ← expand using FOIL
x - 1 = x² - 6x + 9 ( subtract x - 1 from both sides )
0 = x² - 7x + 10 ← in standard form
0 = (x - 2)(x - 5) ← in factored form
Equate each factor to zero and solve for x
x - 2 = 0 ⇒ x = 2
x - 5 = 0 ⇒ x = 5
Substitute these values into (2) for corresponding values of y
x = 2 : y = 2 - 3 = - 1 ⇒ (2, - 1 )
x = 5 : y = 5 - 3 = 2 ⇒ (5, 2 )
Answer:
it either A or B im not sure which one
Step-by-step explanation:
We have been given an image of a circle. We are asked to find the measure of angle JKL.
We can see that angle JML is a central angle of our given circle, so measure of angle JML will be equal to measure of arc JL. So measure of angle JML will be 60 degrees.
We know that tangent of a circle is perpendicular to radius.
We can see that tangent KJ is tangent to circle at point J and tangent KL is tangent to circle at point L. This means that measure of angle KJM and angle KLM will be 90 degrees each.
We can see that JKLM is a quadrilateral. We know that all angles of a quadrilateral add up-to 360 degrees, so we can set an equation as:





Therefore, measure of angle JKL is 120 degrees and option B is the correct choice.