multiply the amount of one piece with the number of pieces
1.85×8=14.8
9514 1404 393
Answer:
$7.14
Step-by-step explanation:
Let p, d, q represent the numbers of pennies, dimes, and quarters in the collection, respectively.
p + d + q = 45 . . . . . . . . there are 45 coins in the collection
2p +5 = q . . . . . . . . . . . . 5 more than twice the number of pennies
p + 4 = d . . . . . . . . . . . . . 4 more than the number of pennies
Substituting the last two equations into the first gives ...
p +(p +4) +(2p +5) = 45
4p = 36 . . . . . . . . . . . . . subtract 9
p = 9 . . . . . . . . . . . divide by 4
d = 9 +4 = 13
q = 2(9) +5 = 23
The value of the collection is ...
23(0.25) +13(0.10) +9(0.01) = 5.75 +1.30 +0.09 = 7.14
The coin collection is worth $7.14.
Answer:
Choice D: Perimeter = 5 + 
+ 
units
Step-by-step explanation:
point B(9, 2) , point C(4, 5), point A (1,1)
Perimeter = D( A, C) + D (A, B) + D (B, C)
where D (A, C) = distance between A and C
so...
D(A, C) = root ( (4 - 1)^2 + (5 - 1)^2) = 5 from a 3-4-5 right triangle.
D(A, B) = root( (9- 1)^2 + (2 -1)^2) = root( 64 + 1) = root(65)
D(B, C) = root( (9 -4)^2 + (2 -5)^2) = root (25 + 9) = root(34)
Perimeter = 5 + root(65) + root(34)
Perimeter = 5 + + units
