B + d = -2d + a solve for b

F(x)= x-2/ x-4

hodyreva [135]

Answer:

The discontinuity is x = 4

There no holes

The equation of the vertical asymptote is x = 4

The x intercept is 2

The equation of the horizontal asymptote is y = 1

Step-by-step explanation:

* Lets explain the problem

∵ $f(x)=\frac{x-2}{x-4}$

- To find the point of discontinuity put the denominator = 0 and find

the value of x

∵ The denominator is x - 4

∵ x - 4 = 0 ⇒ add 4 to both sides

∴ x = 4

* The discontinuity is x = 4

- A hole occurs when a number is both a zero of the numerator

and denominator

∵ The numerator is x - 2

∵ x - 2 = 0 ⇒ add 2 to both sides

∴ x = 2

∵ The denominator is x - 4

∵ x - 4 = 0 ⇒ add 4 to both sides

∴ x = 4

∵ There is no common number makes the numerator and denominator

equal to 0

∴ There no holes

- Vertical asymptotes are vertical lines which correspond to the zeroes

of the denominator of the function

∵ The zero of the denominator is x = 4

∴ The equation of the vertical asymptote is x = 4

- x- intercept is the values of x which make f(x) = 0, means the

intersection points between the graph and the x-axis

∵ f(x) = 0

∴ $\frac{x-2}{x-4}=0$ ⇒ by using cross multiplication

∴ x - 2 = 0 ⇒ add 2 to both sides

∴ x = 2

* The x intercept is 2

- If the highest power of the numerator = the highest power of the

denominator, then the equation of the horizontal asymptote is

y = The leading coeff. of numerator/leading coeff. of denominator

∵ The numerator is x - 2

∵ The denominator is x - 4

∵ The leading coefficient of the numerator is 1

∵ The leading coefficient of the denominator is 1

∴ y = 1/1 = 1

* The equation of the horizontal asymptote is y = 1

6 0

2 years ago

What is 65,759.59 rounded to the nearest tenth

coldgirl [10]

65,759.60

Hope this helps

6 0

3 years ago

a wire of length 200 cm is cut into two parts and each part is bent to form a square.If the area of the larger square is 9 times

diamong [38]

Answer:

The perimeter of the larger square is $150cm.$

Step-by-step explanation:

First of all, let one part of it be " $x$ "

and the other part of it " $200-x$ "

Now to solve this :

The area of the square = $L^2$

The area of one part of the square = $x^2$

The area of the other part of the square = $(200-x)^2$

$9x^2= (200-x)^2\\9x^2=40000-400x+x^2$

Now, add, $-4x^2$ to both the sides :

$9x^2-9x^2=40000-400x+x^2-9x^2\\-1(8x^2+400x-40000)=0$

Now, take out the "8" which is common :

$-8(x^2+50x-5000)=0$

Now, divide it by $-8$ :

$x^2+100x-50x-5000=0\\x(x+100)-50(x+100)=0\\(x+100)(x-50)=0\\$

$x=-100$ or $50$

So, now we know that :

One of the part is = $50cm$

And the other part is = $150cm$

Thus the perimeter of the larger square is = $150cm$

3 0

3 years ago

Need help ASAP please

viva [34]

It would be 3,8
https://www.bing.com/videos/search?q=how+to+solve+a+slope+intercept+form&docid=608053494459401091&mi...
Watch this video it helped to understand how to do these

4 0

2 years ago

Explain what SOHCAHTOA means.

FinnZ [79.3K]

Answer:

It's a mnemonic device to help you remember the three basic trig ratios used to solve for missing sides and angles in a right triangle. It's defined as: SOH: Sin(θ) = Opposite / Hypotenuse. CAH: Cos(θ) = Adjacent / Hypotenuse.

5 0

3 years ago