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2 years ago

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Mathematics

1 answer:

nydimaria [60]2 years ago

7 0

Answer:

I attached a pic of my work, its 100% correct.

Its a bit messy....

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GIVING BRAINLIEST AND THE REST OF MY POINTS, PLS HELP!!!! :((

Nataly_w [17]

Answer:

The correct line plot is choice C.

Step-by-step explanation:

If you look at the data values, you'll notice that there are three $11\frac{1}{4}$ , and the only line plot that depicts this is choice C, so that is the correct answer.

7 0

3 years ago

How to find the solution(s) to:x^2=64

KATRIN_1 [288]

Answer:

Step-by-step explanation:

4 0

3 years ago

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1) Determine the discriminant of the 2nd degree equation below:

Aleksandr-060686 [28]

$\LARGE{ \boxed{ \mathbb{ \color{purple}{SOLUTION:}}}}$

We have, Discriminant formula for finding roots:

$\large{ \boxed{ \rm{x = \frac{ - b \pm \: \sqrt{ {b}^{2} - 4ac} }{2a} }}}$

Here,

x is the root of the equation.
a is the coefficient of x^2
b is the coefficient of x
c is the constant term

1) Given,

3x^2 - 2x - 1

Finding the discriminant,

➝ D = b^2 - 4ac

➝ D = (-2)^2 - 4 × 3 × (-1)

➝ D = 4 - (-12)

➝ D = 4 + 12

➝ D = 16

2) Solving by using Bhaskar formula,

❒ p(x) = x^2 + 5x + 6 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5\pm \sqrt{( - 5) {}^{2} - 4 \times 1 \times 6 }} {2 \times 1}}}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm \sqrt{25 - 24} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm 1}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 2 \: or - 3}}}$

❒ p(x) = x^2 + 2x + 1 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{ {2}^{2} - 4 \times 1 \times 1} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{4 - 4} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm 0}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 1 \: or \: - 1}}}$

❒ p(x) = x^2 - x - 20 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 1) \pm \sqrt{( - 1) {}^{2} - 4 \times 1 \times ( - 20) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ 1 \pm \sqrt{1 + 80} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{1 \pm 9}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 5 \: or \: - 4}}}$

❒ p(x) = x^2 - 3x - 4 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 3) \pm \sqrt{( - 3) {}^{2} - 4 \times 1 \times ( - 4) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm \sqrt{9 + 16} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm 5}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 4 \: or \: - 1}}}$

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5 0

3 years ago

Read 2 more answers

The ratio of cassette to compact disc is 10 to 3 and the number of cassettes is 10 less than 5 times the number of compact discs

OlgaM077 [116]

There are 20 cassettes.

Step-by-step explanation:

Given,

Ratio of cassette to compact disc = 10:3

Let,

the number of cassettes = 10x

Number of compact disc = 3x

According to given statement;

the number of cassettes is 10 less than 5 times the number of compact discs.

10x = 5(Number of CD) - 10

$10x=3(5x)-10 \\10x=15x-10\\10=15x-10x\\10=5x\\5x=10$

Dividing both sides by 5

$\frac{5x}{5}=\frac{10}{5}\\x=2$

Number of cassettes= 10x = 10(2) = 20

There are 20 cassettes.

Keywords: variable, ratio

Learn more about variables at:

#LearnwithBrainly

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3 years ago

PLEASE HELP HELP HELP HELP I GIVE POINTS THIS IS HARD PLEASE HELP<br> WHATS 1+1

Zolol [24]

The answer to your very hard question was very hard to do but the answer is 2

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3 years ago

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