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alexgriva [62]
4 years ago
7

Given ONL=MLN, O and M are right angles prove LM=NO

Mathematics
1 answer:
lara [203]4 years ago
4 0
<span>Yes, it does in fact prove that. It proves that because O and M are on the outer boundaries and once taken away LM=NO as a matter of fact.</span><span />
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If you want to know how fast a tiger can run, which measurement would you see. A. candela, mole B. meter, kilogram C. kilogram,
ElenaW [278]

The answer is D. meter, second

You would want to measure the speed with distance/time, and D is the only answer with both a distance measurement and a time measurement

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Subtract (7x^5-12x^2y+33y^2) from (5x^5-5x^2y+9y^2) simplify your results:
hoa [83]

Answer:

<em>- 2 </em>x^{5}<em> + 7x²y - 24y² </em>

Step-by-step explanation:

( 5 x^{5} - 5x²y + 9y² ) - ( 7 x^{5}  - 12x²y + 33y² ) =

5 x^{5} - 5x²y + 9y² -  7 x^{5}  + 12x²y - 33y² =

( 5 x^{5} - 7 x^{5} ) + ( - 5x²y + 12x²y ) + ( 9y² - 33y² ) =

<em>- 2 </em>x^{5}<em> + 7x²y - 24y²</em>

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3 years ago
What is the range of <br><br> HURRY!
Sedaia [141]

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3 years ago
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Solve the problem 16/50=x/156.25 what is x?
Ne4ueva [31]

Answer:

Step-by-step explanation:

cross multiply

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3 years ago
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The power generated by an electrical circuit (in watts) as a function of its current ccc (in amperes) is modeled by: P(c)=-12c^2
g100num [7]

Answer:

5 amperes will produce the maximum power of 300 watts.

Step-by-step explanation:

The general form of a quadratic function presents the function in the form

f(x)=ax^2+bx+c

The vertex of a quadratic function is the highest or lowest point, also known as the maximum or minimum of a quadratic function.

We can define the vertex by doing the following:

  • Identify a, b, and c
  • Find, the x-coordinate of the vertex, by substituting a and b into

x-coordinate =-\frac{b}{2a}

  • Find, the y-coordinate of the vertex, by evaluating

y-coordinate =f(x-coordinate )=f(-\frac{b}{2a} )

We know that the power generated by an electrical circuit is modeled by

P(c)=-12c^{2}+120c

This function is a quadratic function.

To find the current that produce the maximum power you must

  • Identify a and b

a = -12 and b = 120

  • Find, the maximum current of the vertex, by substituting a and b into

maximum-current =-\frac{b}{2a}

maximum-current =-\frac{120}{2(-12)}\\\\maximum-current = 5

  • Find, the maximum-power, by evaluating

maximum-power =P(maximum-current)=P(-\frac{b}{2a} )

P(5)=-12(5)^{2}+120(5)=300

5 amperes will produce the maximum power of 300 watts.

We can check our work with the graph of the function P(c)=-12c^{2}+120c and see that the maximum is (5, 300).

5 0
4 years ago
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