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2 years ago

X+6y=12 graphed on a coordinate plane

Mathematics

1 answer:

Butoxors [25]2 years ago

3 0

568732\1234321\5678765\8910198

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What is the absolute value of |6|

motikmotik

Answer:

Step-by-step explanation:

7 0

3 years ago

A concession stand at an athletic event is trying to determine how much to sell cola and iced tea for in order to maximize reven

Cerrena [4.2K]

Solution :

Demand for cola : 100 – 34x + 5y

Demand for cola : 50 + 3x – 16y

Therefore, total revenue :

x(100 – 34x + 5y) + y(50 + 3x – 16y)

R(x,y) = $100x-34x^2+5xy+50y+3xy-16y^2$

$R(x,y) = 100x-34x^2+8xy+50y-16y^2$

In order to maximize the revenue, set

$R_x=0, \ \ \ R_y=0$

$R_x=\frac{dR }{dx} = 100-68x+8y$

$R_x=0$

$68x-8y=100$ .............(i)

$R_y=\frac{dR }{dx} = 50-32x+8y$

$R_y=0$

$8x-32y=-50$ .............(ii)

Solving (i) and (ii),

4 x (i) ⇒ 272x - 32y = 400

(ii) ⇒ (-<u>) 8x - 32y = -50 </u>

264x = 450

∴ $x=\frac{450}{264}=\frac{75}{44}$

$y=\frac{175}{88}$

So, x ≈ $ 1.70 and y = $ 1.99

R(1.70, 1.99) = $ 134.94

Thus, 1.70 dollars per cola

1.99 dollars per iced ted to maximize the revenue.

Maximum revenue = $ 134.94

4 0

3 years ago

Which ten thousand does 117,290 round to

Leni [432]

Answer:

120,000

Step-by-step explanation:

because seven in greater than 5 so it would round up

3 0

2 years ago

Paul paid $ 25.50 for 3 cups of hot chocolate and cups of tea. The cost of each cup of tea was 2/3 the cost of each cup of hoy c

Allushta [10]

Let the cost of one cup of hot chocolate be = x

Let the cost of one cup of hot tea be = y

Paul paid $ 25.50 for 3 cups of hot chocolate and 4 cups of tea.

Equation becomes = $3x+4y=25.50$ ...(1)

As given, the cost of each cup of tea was 2/3 the cost of each cup of hot chocolate.

$y=\frac{2x}{3}$ .... (2)

Putting the value of y from (2) in (1)

$3x+4(\frac{2x}{3})=25.50$

= $3x+\frac{8x}{3}=25.50$

= $\frac{9x+8x}{3}=25.50$

= $17x=76.5$

x=4.5

$y=\frac{2x}{3}$

= $\frac{2*4.5}{3}$

y =3

Hence each cup of hot chocolate is $4.50

Each cup of tea is $3.

7 0

3 years ago

At a local coffee shop, three coffees and two muffins cost a total of $7.00. Two coffees and four

rewona [7]

Answer:

$10.25

Step-by-step explanation:

Set up a system of equations, so 3c + 2m = 7 and 2c + 4m = 8, where c = the cost of coffees, and m = cost of muffins

To solve multiply the first equation by -2(3c + 2m=7) so you get -6c -4m = -14 now add the two equations

-6c - 4m = -14

2c + 4m = 8 notice that -6c + 2c = -4c and -4m + 4m cancels, then -14+8=-6

so we have -4c = -6 so c = $1.50

To solve for m, substitute c = 1.50 so 3(1.50) + 2m = 7, so solve for m so

4.5 + 2m = 7, 2m = 2.5, so m = $1.25

So now solve the final problem 6(1.50) + 1(1.25) = $10.25

6 0

2 years ago