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3 years ago

Predict the number of roses in a garden with 16 sunflowers if there are 3 sunflowers in a garden with 81 roses.

2 answers:

6 0

Set up a proportion.
3 sunflowers/ 81 roses= 16 sunflowers/xroses

Cross multiply:
81*16=1296
1296/3= 432

Final answer: 432 roses

Allisa [31]3 years ago

4 0

81*16=1296
1296\3=432

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PLEASE HELP ITS DUE TODAYYY

Bumek [7]

Answer:

(-3,10) (0,5) (3,0) (6,-5)

Step-by-step explanation:

x intercept = 3

y intercept =5

If brainiest is earned its greatly appreciated

6 0

2 years ago

12. Write the first five terms of two different sequences that have 10 as the

kodGreya [7K]

Answer:

a) The arithmetic sequence with common difference 2 that has 8 as the first term.

b) The arithmetic sequence of common difference -5 and first term 15.

Step-by-step explanation:

Let's use for example the arithmetic sequence with common difference 2 that has 8 as the first term. Then the first two terms of this sequence are:

8, and (8+2) = 10 Therefore the second term is 10.

Another arithmetic sequence of common difference -5 and first term 15. The firs two terms of this sequence are:

15, and (15 - 5) = 10. Therefore again a 10 as second term.

6 0

3 years ago

Given a trapezoid with a height of 4.3m and bases of 9.2 m and 3.2m, what is the area of the trapezoid? Do not include units in

77julia77 [94]

For a height of 4.3m and bases of 9.2 m and 3.2m, the area of the trapezoid is mathematically given as

A=26.7

<h3>What is the area of the trapezoid?</h3>

Generally, the equation for the trapezoid is mathematically given as

A=0.5*(a+b)*h

Therefore

A=0.5*(3.2+9.2)*4.3

A=26.7

In conclusion,area of the trapezoid

A=26.7

Read more about Arithmetic

brainly.com/question/22568180

7 0

1 year ago

a dog eats 5 cups of food a day. a pound of food contains 10.5 cups. how much does it cost to feed the dog each day if a 50 lb b

Stells [14]

So, the dog eats 5 cups a day and 1 pound of dog food is 10.5 cups.

A 50 lb bag is<span> $22.50.

Since you're asking how much it would cost to feed it a day we need to find out how much 1 pound of food costs.

</span>22.50 / 50 = 0.45

So, it's 0.45 for 1 lb. But 1 lb is 10.5 cups, not 5.

0.45 / 5 = 0.09

So, I believe it would cost 0.09 each day to feed the dog.

3 0

2 years ago

Calcium is an essential nutrient for strong bones and for controlling blood pressure and heart beat. Because most of the body’s

irakobra [83]

Answer:

No, because the 95% confidence interval contains the hypothesized value of zero.

Step-by-step explanation:

Hello!

You have the information regarding two calcium supplements.

X₁: Calcium content of supplement 1

n₁= 12

X[bar]₁= 1000mg

S₁= 23 mg

X₂: Calcium content of supplement 2

n₂= 15

X[bar]₂= 1016mg

S₂= 24mg

It is known that X₁~N(μ₁; σ²₁), X₂~N(μ₂;δ²₂) and σ²₁=δ²₂=?

The claim is that both supplements have the same average calcium content:

H₀: μ₁ - μ₂ = 0

H₁: μ₁ - μ₂ ≠ 0

α: 0.05

The confidence level and significance level are to be complementary, so if 1 - α: 0.95 then α:0.05

since these are two independent samples from normal populations and the population variances are equal, you have to use a pooled variance t-test to construct the interval:

[(X[bar]₁-X[bar]₂) ± $t_{n_1+n_2-2;1-\alpha /2}$ * $Sa*\sqrt{\frac{1}{n_1} +\frac{1}{n_2} }$ ]

$t_{n_1+n_2-2;1-/2}= t_{25;0.975}= 2.060$

$Sa= \sqrt{\frac{(n_1-1)S^2_1+(n_2-1)S^2_2}{n_1+n_2-2} }= \sqrt{\frac{11*529+14*576}{12+15-2} } = 23.57$

[(1000-1016)±2.060*23.57* $\sqrt{\frac{1}{12} +\frac{1}{15} }$ ]

[-34.80;2.80] mg

The 95% CI contains the value under the null hypothesis: "zero", so the decision is to not reject the null hypothesis. Then using a 5% significance level you can conclude that there is no difference between the average calcium content of supplements 1 and 2.

I hope it helps!

3 0

2 years ago