Answer:
If y(x-y)^2=x, then int1/(x-3y)dx is equal to (A) 1/3log{(x-y)^2+1} (B) 1/4log{(x-y)^2-1} (C) 1/2log{(x-y)^2-1} (D) 1/6 log{(x^2-y^2-1}
Step-by-step explanation:
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Solution given:
y=25 [base side of isosceles triangle]
sin 45=opposite/hypotenuse
sin45=25/x
x=25/sin45
x=25√2
f(x)= -7x+7
