Answer:
The mean is 
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the mean of this normal distribution if the probability of scoring above x = 209 is 0.0228?
This means that when X = 209, Z has a pvalue of 1-0.0228 = 0.9772. So when X = 209, Z = 2.
The mean is
Answer:
The standard deviation (σ) = 0.05
Step-by-step explanation:
The question is to find the standard deviation.
STEEP 1: FIND THE MEAN
(10+9.9) ÷ 2 = 9.95
STEP 2: SQUARE THE DIFFERENCE BETWEEN SPRINT TIME AND MEAN
10-9.95= 0.05
0.05^2 = 0.0025
9.9 - 9.95= -0.0025
-0.0025^2 = 0.0025
STEP 3: FIND THE VARIANCE
0.0025+0.0025= 0.005
0.005/2= 0.0025
STEP 4: FIND THE STANDARD DEVIATION (σ )
√variance
√0.0025 = 0.05
Therefore
σ = 0.05.
From the standard deviation, the percentage probability of the higher value to occurs is
0.05×100= 5%
That means Doug has 95%
And Bob has 5%
Hope this helped you answer your question! Bye bye
Answer:
(-1)(11)(3)(5)
Step-by-step explanation:
First off: -165 separates into the factors (-1) and (165). Next, we divide 165 by 15, obtaining 15(11).
So far, we have (-1)(11)(15).
15 is still factorable. We get:
(-1)(11)(3)(5), which is the desired prime factorization of -165.
Answer:
10.27 feet/sec.
Step-by-step explanation:
The distance traveled by the car, d in feet, is given by the function 
.......... (1), where t is the time in seconds.
So, at t= 2 sec, from equation (1) we get d = 1.1 × 4 = 4.4 feet.
Again, at t = 5 sec, we get d = 1.1 × 32 = 35.2 feet.
Now, average speed of the car from t = 2 sec. to t = 5 sec. will be give by
= 
feet/sec. (Answer)
