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Black_prince [1.1K]
3 years ago
7

The problem has too little information:

Mathematics
2 answers:
Snowcat [4.5K]3 years ago
8 0
Carl’s horse travels 60 feet in one complete turn of the carsouel
ad-work [718]3 years ago
7 0

Answer:

  about 30 ft

Step-by-step explanation:

Statements A, B, C, D are (approximately) correct.

Using the observations in A and B, Carl's horse travels farther by ...

  90 ft - 60 ft = 30 ft . . . in one complete turn

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Find the seventh term of the sequence which has a first term of 1/2 and has a common ratio of three
prohojiy [21]

The seventh term of the sequence is 364.5

<h3>Geometric progression </h3>

From the question, we are to determine the seventh term of the sequence

Using the formula,

a_{n}  = ar^{n-1}

Where a_{n} is the nth term

a is the first term

and r is the common ratio

From the given information,

a = 1/2

r = 3

Thus,

a_{7}  = (\frac{1}{2}) 3^{7-1}

a_{7}  = (\frac{1}{2}) 3^{6}

a_{7}  = \frac{1}{2} \times  729

a_{7}  = 364\frac{1}{2} \ OR \ 364.5

Hence, the seventh term of the sequence is 364.5

Learn more on Geometric progression here: brainly.com/question/24643676

#SPJ1

3 0
2 years ago
A pipe is 30 feet long. it need to be cut into pieces that are each 2/3 ft long how many pieces can be made from the pipe? answe
AysviL [449]

Answer:

Divide total length by length of each piece to get the number of pieces.

= 30 ÷ 2/3

multiply by reciprocal of 2/3

= 30 * 3/2

= 90/2

= 45

ANSWER: Total number of pieces that can be cut is 45.

7 0
3 years ago
Which is the best estimate for the mass of a rose
andre [41]

Answer:

Step-by-step explanation:

dtuyhgtrfedfgrthyuj

4 0
3 years ago
1. What will be the letter in the following sequence?
svetlana [45]

Answer:

1. G

2. Not sure what you are ask

5 0
3 years ago
Pleaseeee helpppp !!!!!!!!! Will mark Brianliest !!!!!!!!!!!
Semenov [28]

Answer:

KL = 50

Step-by-step explanation:

∆JML is similar to ∆JNL. it follows that:

[tex] \frac{JM}{JN} = \frac{JL}{JK} [\tex]

JM = 4 + 20 = 24

JN = 4

JL = 10 + KL

JK = 10

Plug in the values

[tex] \frac{24}{4} = \frac{10 + KL}{10} [\tex]

[tex] 6 = \frac{10 + KL}{10} [\tex]

Multiply both sides by 10

[tex] 6*10 = \frac{10 + KL}{10}*10 [\tex]

[tex] 60 = 10 + KL [\tex]

Subtract 10 from each side

[tex] 60 - 10 = KL [\tex]

[tex] 50 = KL [\tex]

KL = 50

6 0
3 years ago
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