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Bond [772]
3 years ago
8

Which of the following could represent a diver’s position in relation to the surface of the water after diving into a pool?

Mathematics
1 answer:
bulgar [2K]3 years ago
3 0

Answer:

-2 meters

-3.1 meters

- 2 1/2 meters

Step-by-step explanation:

I did them and I got it right!

pls brainlest me

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What are the clear steps for solving for x question (5x + 2)
Alenkinab [10]

Answer:

x= -2/5

Step-by-step explanation:

(5x+2)=0

    -2   -2

5x=-2

------------

    5

x= -2/5

6 0
3 years ago
What is the simplified expression for
kiruha [24]
5/2 should be as simplified as it can get. Hope this helps!
6 0
3 years ago
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The cost of 90 kg of rice is 4500. what is the cost of 2 quintal of rice?​
gayaneshka [121]

Answer:

The cost of 2 quintal of rice is $10,000.

Step-by-step explanation:

To determine the cost of 2 quintals of rice, knowing that 90 kilos of said product is worth $ 4,500, it is first necessary to establish the equivalence between quintals and kilograms. In this regard, a quintal is equivalent to 100 kilograms, so 2 quintals are equivalent to 200 kilos.

Now, to determine the cost per kilogram of rice, the following calculation is required:

4,500 / 90 = X

50 = X

Therefore, 1 kilogram of rice costs $ 50. Thus, since 200 x 50 equals 10,000, 2 quintals of rice will cost $ 10,000.

5 0
3 years ago
A rectangular field is 450 meters long and 300 meters wide. What is the area of the field in square kilometers?
rodikova [14]
First you multiply 450 m ×300 m= 135,000 m
Then you convert to Kilometers 135,000 ÷1,000= 135 Kilometers

So the answer is 135 Kilometers
7 0
3 years ago
Premier Bank is planning to have a new building constructed. They would like the length of the building to be 40 feet longer tha
MaRussiya [10]

Let L, W, F, H, P represent, respectively, the length, width, number of floors, height, and perimeter of the building. Here are some equations that model the given information.

  • L = W + 40
  • H = 12×F
  • foundation cost = 10×L×W
  • cost of floors = 35000×F
  • total cost = foundation cost + cost of floors
  • total cost = 1,180,000
  • P = 2×(L+W)
  • P = 3×H

We can rewrite these into a system of equations involving L, W, F.

Let's look first at the relation between the perimeter and height. The two versions of perimeter are equal to each other, so we have (after substituting for H) ...

... 3H = 2(L+W)

... 3(12F) = 2((W +40) +W) . . . . substitute for H and L

... 36F = 4W +80 . . . . . . . . . . . simplify

... 9F = W +20 . . . . . . . . . . . . . divide by 4

Now, we can look at the cost equations.

... 1180000 = 35000F + 10W(W+40) . . . . . substitute for the various cost terms and for L

... 118000 = 3500F +W² +40W . . . . . . . . . divide by 10

The two simplified equations in W and F are ...

  • 9F = W +20
  • 3500F = 118000 -40W -W²

You can solve the first for F and substitute for F in the second. Then you have a quadratic equation in W that can be solved by the usual methods. (Likely, the quadratic formula would be the best choice.) Here, we have elected to let a graphing calculator show the two solutions. One solution has negative dimensions, so is clearly infeasible.

There is one (nearly feasible) solution:

... W ≈ 180.788

... F ≈ 22.31

There is no combination of floor dimensions and integral numbers of floors that will match <em>all</em> of the problem requirements.

_____

A solution that comes about as close as possible is ...

  • length = 221 ft
  • width = 181 ft
  • perimeter = 804 ft
  • # of floors = 22
  • height = 264 ft . . . . . (3×height = 792 ft vs. 804 ft)
  • cost = $1,170,010 . . . (vs. 1,180,000)

4 0
3 years ago
Read 2 more answers
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