So my step one would be to add the six over and get 3x squared -9x+6=0, then divide by 3 to get x squared-3x+2=0. The next step is seeing what two numbers multiply to 2 but also add to negative three. The two numbers are -1 and -2. So then you are going to make two equations, one being x-1=0 and the other being x-2=0. Solve both to get X=1 and X=2, check your answers in the original equation. Hope this helps!
