2. At a local restaurant, the health inspector visits every 6 days, and the fire inspector visits every 14 days.

1 answer:

3 0

<h2><em>(a)______________________ </em></h2><h2><em> | 1 | 2 | 3 | 4 | </em></h2><h2><em>------------------------------------------- </em></h2><h2><em>Health | 7 | 14 | 21 | 28 | </em></h2><h2><em>Fire | 12 | 24 | 36 | 48 | </em></h2><h2><em>------------------------------------------</em></h2><h2><em> HOPE IT HELPS (◕‿◕✿) </em></h2><h2><em> SMILE!!</em></h2>

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Density of a 8200 gram brick that is 4 inches x 4 inches x 4 inches?

Tanzania [10]

Density = mass / volume
Density = 8,200 grams / (4*4*4)
Density = 8,200 grams / 64 cubic inches
Density = <span> <span> <span> 128.125 </span> </span> </span> grams / cubic inch

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3 years ago

Suppose we have 3 cards identical in form except that both sides of the first card are colored red, both sides of the second car

Nikolay [14]

Answer:

probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3

Step-by-step explanation:

First of all;

Let B1 be the event that the card with two red sides is selected

Let B2 be the event that the

card with two black sides is selected

Let B3 be the event that the card with one red side and one black side is

selected

Let A be the event that the upper side of the selected card (when put down on the ground)

is red.

Now, from the question;

P(B3) = ⅓

P(A|B3) = ½

P(B1) = ⅓

P(A|B1) = 1

P(B2) = ⅓

P(A|B2)) = 0

(P(B3) = ⅓

P(A|B3) = ½

Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;

Thus;

P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]

P(B3|A) = (1/6)/(⅓ + 0 + 1/6)

P(B3|A) = (1/6)/(1/2)

P(B3|A) = 1/3

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3 years ago

The measure of angle 6 is 98°. What is the measure of angle 7?

otez555 [7]

Dude, it's impossible to solve without the pic

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3 years ago