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3 years ago

PPPPLLLLEEEEAAASSSEEE HHHHEEELLLPPP!!!!!!

Mathematics

1 answer:

4vir4ik [10]3 years ago

8 0

The third answer would be correct. TUWV ~ DEFG; 6:4.5

This is because 6 is dilated to 4.5.

Hope this helped!

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Does anyone know this ? Thank you

alina1380 [7]

Answer:

Step-by-step explanation:

angle ACB = 180-130=50 degree

angle ABC = 180 - (94+50)

= 180-144

= 36

6 0

3 years ago

According to the line plot how many apples were weighed

vova2212 [387]

Answer:

14 apples

Step-by-step explanation:

Just count the x

8 0

3 years ago

Read 2 more answers

Craig likes to collect video records last year he had 10 records his collection now has 12 records what is the percent increase

algol [13]

I believe the answer is a 20% increase because 12-10 equals 2. there is a 2 record difference so 2 out of 10 is 1/5 of the whole, but you have to convert the numbers and 1/5 of the whole of 100 is 20. sorry if that didn’t make much sense

6 0

3 years ago

Read 2 more answers

Can someone answer for me please, if you're great at math.

jonny [76]

Assuming that c is the length of AB (as is usually the case in the angle-side notation for triangles):
If sin(35) = 12/c, we can transform by multiplying both sides by c, and dividing both by sin(35) to get
c = 12/sin(35)
Evaluating using a calculator gives 20.92 units.

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=5%28sin%28t%29%20%20%5Cfrac%7Bdy%7D%7Bdx%7D%20%2Bycos%28t%29%29%29%3Dcos%28t%29%20%20%28sin%28

Nataliya [291]

Assuming you mean

$5\sin t\dfrac{\mathrm dy}{\mathrm dt}+5y\cos t=\cos t\sin^2t$

This ODE is linear in $y$ , and you can already contract the left hand side as the derivative of a product:

$\dfrac{\mathrm d}{\mathrm dt}\left[5y\sin t\right]=\cos t\sin^2t$

Integrating both sides with respect to $t$ yields

$5y\sin t=\displaystyle\int\cos t\sin^2t\,\mathrm dt$
$5y\sin t=\dfrac13\sin^3t+C$
$y=\dfrac1{15}\sin^2t+C\csc t$

Given that $y\left(\dfrac\pi2\right)=9$ , we have

$9=\dfrac1{15}\sin^2\dfrac\pi2+C\csc\dfrac\pi2$
$9=\dfrac1{15}+C$
$C=\dfrac{134}{15}$

so that the particular solution over the interval is

$y=\dfrac1{15}\sin^2t+\dfrac{134}{15}\csc t$

6 0

3 years ago