You need two equations to solve a two-variable equation.
X^3 = 1/8
x^3 = (1/2)^3
x = 1/2
hope it helps
3y+14=44
Answer: First step is to subtract 14 from each side
3y = 30 (divide each side by 3)
y = 30/3, y = 10
Let x be the first odd number.
Second odd number will be x+2
Proof:
If 3 (was) the first odd number, 3+2 would be the next which is 5.
So,
(x) (x+2) = 99
xsquare + 2x = 99
xsquare +2x - 99 = 0
xsquare +11x - 9x -99 = 0
x(x +11) -9(x + 11) = 0
(x+11) (x-9) = 0
So the two odd numbers were 9 and 11
