landing on a shaded portion and landing on an even number ; landing on a shaded portion and landing on a number greater than 3 ; landing on an unshaded portion and landing on an odd number ; and landing on an unshaded portion and landing on a number less than 2.

Explanation:

Mutually exclusive events are events that cannot occur at the same time. Our spinner has two grey sections, on 1 and 3; and two white sections, on 2 and 4.

This means that the spinner cannot land on a shaded (grey) portion and land on an even number at the same time, since the grey sections are numbered 2 and 4, both of which are even numbers.

The spinner also cannot land on a shaded (grey) portion and land on a number greater than 3 at the same time; this is because the only number greater than 3 on the spinner is 4, which is a white portion.

The spinner cannot land on an unshaded (white) portion and land on an odd number, since the white sections are labeled 2 and 4, which are both even.

The only number on the spinner less than 2 is 1, which is grey; this means the spinner cannot land on a number less than 2 and an unshaded (white) portion at the same time.

5 0

3 years ago

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What is the stem and leaf plot

jenyasd209 [6]

This is what a Stem and Leaf plot work. Do you know how to use it?

8 0

3 years ago

Liliana is making a vase with a circular base. She wants the area of the base to be between 135 cm2 and 155 cm2. Which circle co

Umnica [9.8K]

Answer:

(b) Circle C is shown. Line segment A C is a radius with length 7 centimeters.

Step-by-step explanation:

Given

$Minimum\ Area = 135cm^2$

$Maximum\ Area = 155cm^2$

$\pi = 3.14$

Required

Which circle could she use

To do this, we simply calculate the areas of all the given circles

The area of a circle is:

$Area = \pi r^2$

Where

$r = radius$

$a.\ r = 6cm$

The area is calculated as thus:

$Area = \pi r^2$

$Area = 3.14 * (6cm)^2$

$Area = 3.14 * 36cm^2$

$Area = 114.04cm^2$

$b.\ r = 7cm$

The area is calculated as thus:

$Area = \pi r^2$

$Area = 3.14 * (7cm)^2$

$Area = 3.14 * 49cm^2$

$Area = 153.86cm^2$

$c.\ r = 8cm$

The area is calculated as thus:

$Area = \pi r^2$

$Area = 3.14 * (8cm)^2$

$Area = 3.14 * 64cm^2$

$Area = 200.96cm^2$

$d.\ r = 9cm$

The area is calculated as thus:

$Area = \pi r^2$

$Area = 3.14 * (9cm)^2$

$Area = 3.14 * 81cm^2$

$Area = 254.34cm^2$

From the calculations above; only the circle in option (b) has an area within the required range of 135 to 155cm^2

6 0

3 years ago

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Ashraf attends a local festival, which has an entrance fee. Each game costs

irina1246 [14]

Answer:

2 + 2x = y

Step-by-step explanation:

I think you're saying the entrance fee is $2. This is the constant. If each game costs an additional $2 per game, that would translate into 2x - or 2 * the number of games. This results in the slope-intercept form equation of: 2+2x=y

5 0

3 years ago