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mars1129 [50]
3 years ago
9

Which triangle is similar to △ABC if sin(A) = , cos(A) = , and tan(A) = ?

Mathematics
2 answers:
GREYUIT [131]3 years ago
6 0

Answer:

It is given that In Δ ABC

sin A=\frac{1}{4},cos A=\frac{\sqrt{15}}{4}, tan A=\frac{1}{\sqrt{15}}

Length of perpendicular = 1=AB

length of Hypotenuse =4=AC

Length of Base = √15=BC

In ΔYZX

Length of perpendicular =6 =YZ

length of Hypotenuse =24=ZX

Length of Base = 6√15=XY

ΔYZX is similar to ΔABC, because when triangles are similar their sides are proportional.

\frac{AB}{YZ}=\frac{BC}{XZ}=\frac{AC}{XY}=\frac{1}{6}

vekshin13 years ago
4 0
The answers D homie:)
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Answer any problem and I will be happy <br> (30) pts
KatRina [158]
Problem 4

c = speed of current
p = paddling speed in still water

Against current:
speed = p-c (start with paddling speed and subtract off current's speed)
speed = 2 (given)
p-c = 2
p = 2+c

With the current
speed = p+c (now the current is speeding things up, so we add on c)
speed = 3 (given)
p+c = 3
2+c+c = 3 ... plug in p = 2+c; solve for c
2+2c = 3
2+2c-2 = 3-2
2c = 1
c = 1/2
c = 0.5

Since c = 0.5, we can use this to find p
p = 2+c
p = 2+0.5
p = 2.5

So,
The speed of the river current is 0.5 mph
Rita's paddling speed in still water is 2.5 mph

==================================================

Problem 5

Terms to know:
headwind = wind that slows the plane down (wind is coming from the head of the plane flowing in the opposite direction of the plane's intended direction)
tailwind = wind that speeds the plane up (wind is coming from the tail of the plane flowing in the same direction of the plane's intended direction)

d = distance = 255 miles
p = speed of plane in still air
w = speed of wind

Against the wind (headwind), the plane travels 1.7 hours at some speed p-w. We start with the plane's speed in still air (p) and subtract off the wind speed because the wind is slowing the plane down. So the first equation is
(p-w)*1.7 = 255
since the plane travels 255 miles
I'm using the formula d = r*t
d = distance
r = rate or speed
t = time

Divide both sides of (p-w)*1.7 = 255 by 1.7 and we get p-w = 150
Then add w to both sides and we have p = 150+w

Similarly, the second equation is 
(p+w)*1.5 = 255
since the tailwind speeds the plane up from p to p+w, the time is 1.5 hrs and the distance is the same (255 mi)

Plug the equation p = 150+w into the second equation
(p+w)*1.5 = 255
(150+w+w)*1.5 = 255
(150+2w)*1.5 = 255
150*1.5+2w*1.5 = 255
225+3w = 255
225+3w-225 = 255-225
3w = 30
3w/3 = 30/3
w = 10

Use w = 10 to find p
p = 150+w
p = 150+10
p = 160

So,
wind speed = 10 mph
speed of plane in still air = 160 mph
6 0
3 years ago
If 0.00005893 is expressed in the form 5.893 × 10n, what is the value of n ?
yan [13]
In the scientific value of 5.893 x 10n. The standard value is 0.00005893 what is n? To better illustrate this phenomenon, we can explain it further under the rules of scientific notation.
For example. <span><span>
1. </span><span> 3 x 10^3 = 3 x 100 = 300</span></span>
<span><span>2. </span><span> 3 x 10^-3 = 3 x 0.001 = 0.003</span></span>

Solution:
0.00005893 = 5.893 x 0.00001 = 5.893 x 10^-5  
n= ^-5



7 0
3 years ago
What is 85% converted to a fraction?
Ksju [112]
The answer to the question is 85/100
6 0
3 years ago
Which statement best explains the relationship between lines FG and HJ?
murzikaleks [220]

Answer:

(D)

Step-by-step explanation:

From the figure, we have

The coordinates of the point F are: (-4,1).

The coordinates of the point G are: (0,-2)

The coordinates of the point J are: (0,4) and

The coordinates of the point H are: (-4,-2).

Now, the slope of the line FG is :

S=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

S=\frac{-2-1}{0+4}

S=\frac{-3}{4}

And, the slope of the line HJ is:

S=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

S=\frac{-2-4}{-4-0}

S=\frac{3}{2}

Now, the slope of FG=\frac{1}{slope of HJ}

\frac{-3}{4}=\frac{2}{3}

which is not possible, thus They are not perpendicular because their slopes are not negative reciprocals.

6 0
3 years ago
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A 4 pound roast must be cooked for 30 minutes per pound and must rest for 15 minutes when must it be put into the oven in order
Alinara [238K]
So put it in 2 hours and 15 minutes before 6pm which would be 3:45
4 0
3 years ago
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