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seropon [69]
2 years ago
5

Solve the following inequality 4x+15≥x+6

Mathematics
2 answers:
WINSTONCH [101]2 years ago
8 0

Answer:

  • \boxed{\sf{x\geq -3}}

Step-by-step explanation:

The following inequality can be solved by separating the term x from one side.

4x+15≥x+6

<u>First, subtract by 15 from both sides.</u>

4x+15-15≥x+6-15

<u>Solve.</u>

4x≥x-9

<u>Then, you subtract by x from both sides.</u>

4x-x≥x-9-x

<u>Solve</u>.

3x≥-9

<u>Divide by 3 from both sides.</u>

3x/3≥-9/3

<u>Solve.</u>

<u>Divide the numbers from left to right.</u>

-9/3=-3

\Longrightarrow: \boxed{\sf{x\geq -3}}

  • <u>Therefore, the correct answer is x≥-3.</u>

<u></u>

I hope this helps, let me know if you have any questions.

Mariana [72]2 years ago
4 0

Answer:

x ≥ -3

Step-by-step explanation:

To determine the solution to the inequality, we need to isolate the variable and its coefficient on one side of the equation. Furthermore, isolate the variable by dividing the coefficient by both sides of the equation. The inequality obtained after doing these steps is the solution to the inequality.

<u>Given inequality:</u>

  • 4x + 15 ≥ x + 6

As said above, let's isolate "x" and it's coefficient on one side of the equation. This can be done by subtracting "x + 15" to both sides of the equation.

  • ⇒ 4x + 15 - (x + 15) ≥ x + 6 - (x + 15)
  • ⇒ 4x + 15 - x - 15 ≥ x + 6 - x - 15
  • ⇒ 3x ≥ -9

As said above, let's further isolate "x" by dividing the coefficient of "x" to both sides of the equation.

  • ⇒ 3x/3 ≥ -9/3
  • ⇒ x ≥ -3

Therefore, the solution is x ≥ -3.

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2. You know that y=\frac{sinx}{cosx} with cosx\neq 0, because the division by zero is not defined. So , cosx=0 for \frac{(2n+1)\pi}{2} where n is a integer number.

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