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navik [9.2K]
3 years ago
5

Find a 2 digit number less than 50 using these clues. It can be divided by 4 exactly. When 4 is added to it, it can be divided b

y 5.
Mathematics
2 answers:
skad [1K]3 years ago
5 0
The answer is 36 (Don't mind the comment, I forget you could edit the answer)

36 / 4 = 9

36 + 4 = 40
40 / 5 = 8


antiseptic1488 [7]3 years ago
5 0
The answer is 16
4•4=16
16+4=20
20/5= 4
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Write your answer in simplest radical form​
Bess [88]

Answer:

z = √3

Step-by-step explanation:

sin (30°) = z / 2√3

z = sin (30°) 2√3

z = √3

4 0
3 years ago
A large university accepts ​40% of the students who apply. Of the students the university​ accepts, 35​% actually enroll. If 300
JulijaS [17]

Answer:

the  students enroll is 4,200

Step-by-step explanation:

The computation of the students enroll is shown below:

= Number of students × applied percentage × enrolled percentage

= 30,000 × 40% × 35%

= 4,200

hence, the  students enroll is 4,200

6 0
2 years ago
2(4y-5)=70<br><br>how u do this​
steposvetlana [31]

Answer:

Step-by-step explanation:

First you distribute so two times 4Y is 6Y then you multiply the two in the five which gives you 2Y -5 equals 70

3 0
3 years ago
Read 2 more answers
For a particular​ event, 771 tickets were sold for a total of ​$3037. If students paid ​$3 per ticket and non-students paid ​$5
BlackZzzverrR [31]

Answer:

Number of student tickets were sold = 409

Step-by-step explanation:

Total number of tickets sold = 771

I.e Students ticket (S) + Non students ticket(N S)  = 771

Total amount to be paid for tickets = $ 3037

Amount paid by students per tickets = $3

Amount paid by non-students per tickets = $5

So, according to question

S + NS = 771

3 S + 5 NS = 3037

Solve both equations  

5 S + 5 NS = 771 × 5

3 S + 5 NS = 3037

so ,

(5 S + 5 NS) - (3 S + 5 NS ) = 3855 - 3037

Or, 2 S = 818

I.e S = \frac{818}{2} = 409

Hence, The number of student tickets were sold = 409      Answer

5 0
3 years ago
How many 4 digit multiples can not be divided by 5
Advocard [28]

Answer:

1800

Step-by-step explanation:

Let us solve this question by Modular Airthmatic.

Let the lowest 4 digit number be X.

X= 1 (mod 5)

X =2 (mod 5)

X=3 (mod 5)

X =4 (mod 5)

X=1+5 t where t is any integer.

1+5 t=2 (mod 5)

5 t=1 (mod 5 )

5 is the Modular Inverse of modulo 5

t=1 (mod 5)

t =1+5 u : u= any integer.

X becomes 1+ 5 (1+5u )=6+25 u

6+25u =3 (mod 5)

25 u= -3 (mod 5)=2 (mod 5)

25 is Modular Inverse of Modulo 5

u=2 (mod 5)

u =2+5 v : v= any integer.

X becomes 6 +25 (2+5 v)=56+125 v .

56 +125 v=4 (mod 5)

125 v=-52 (mod 5)=3 (mod 5)

125 is Modular Inverse of modulo 5

v = 3 (mod 5)

v =3 +5 w where w is any integer.

For lowest 4 digit number, take

w=200

X=1003 : Lowest 4 digit number.

Take w=201

X=208 : Next number.

For 4 digit largest number, take

w=1995

X= 9978 : Largest number.

No. of Numbers =(1995 - 200 )+1=1800 □Ans.

8 0
3 years ago
Read 2 more answers
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