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Gnesinka [82]
3 years ago
13

An electronics retailer receives a shipment of 6,000CDs to distribute to its stores. A quality control manager inspects a random

sample of 40 CDs and finds that 2 are defective. How many CDs in the shipment are likely to be defective? Show your work
Mathematics
2 answers:
Alex17521 [72]3 years ago
8 0

Answer: 300

Step-by-step explanation:

Given , An electronics retailer receives a shipment of 6,000CDs to distribute to its stores.

i.e, Total CD's he has now = 6,000

Also, a quality control manager inspects a random sample(S) of 40CD's , the number of defective(D) CD's are 2.

Then , the proportion of defective( D) CD's = \dfrac{D}{S}=\dfrac{2}{40}=0.05

Now , the number of CDs in the shipment are likely to be defective = ( Total CD's) x (proportion of defective CD's)

= 6000 x 0.05

=300

Hence, the number of CDs in the shipment are likely to be defective  =300

swat323 years ago
3 0

Answer:

heh

Step-by-step explanation:

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Let x, x + 1 two consecutive integers;
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10 points. Please help me with numbers 9-13.<br> Numbers 9-13 is the picture.
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Answer:

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Step-by-step explanation:

Remark

Step One

The main step is to realize that if the lower left hand angle is 90 degrees, then the upper left hand angle is also 90. That is because the interior angles of parallel lines are supplementary. If one of the angle is 90 degrees, so is the other.

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Step Two

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5(y + 11) + 4y -  10 + 180 = 360            Combine again

5(y + 11) + 4y + 170 = 360                   Subtract 170 from both sides

5(y + 11) + 4y = 360 - 170                     Combine like terms

5(y + 11) + 4y = 190                             Remove the brackets

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9y = 190 - 55

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konstantin123 [22]

Answer:

After solve the equations we get value of k=3

Step-by-step explanation:

We need to find value of k for which the lines x+2y=0, 3x-4y-10=0 and 5x+ky-7=0 are concurrent.

If the lines are concurrent, they pass through same point.

Let:

x+2y=0--eq(1)\\ 3x-4y-10=0--eq(2)\\ 5x+ky-7=0--eq(3)

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From eq(1) we find value of x and put it in eq(2)

From \ eq(1) x+2y=0\\x=-2y\\Put x=-2y \ in \ eq(2)\\3x-4y-10=0\\3(-2y)-4y-10=0 \\-6y-4y=10\\-10y=10\\y=\frac{10}{-10}\\y=-1

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So, After solve the equations we get value of k=3

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