An electronics retailer receives a shipment of 6,000CDs to distribute to its stores. A quality control manager inspects a random
2 answers:
Answer: 300
Step-by-step explanation:
Given , An electronics retailer receives a shipment of 6,000CDs to distribute to its stores.
i.e, Total CD's he has now = 6,000
Also, a quality control manager inspects a random sample(S) of 40CD's , the number of defective(D) CD's are 2.
Then , the proportion of defective( D) CD's =
Now , the number of CDs in the shipment are likely to be defective = ( Total CD's) x (proportion of defective CD's)
= 6000 x 0.05
=300
Hence, the number of CDs in the shipment are likely to be defective =300
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The answer is 
, or 0.0133.
Answer:
The highest total cholesterol level a man in this 35–44 age group can have and be in the lowest 10% is 160.59 milligrams per deciliter.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
Find the highest total cholesterol level a man in this 35–44 age group can have and be in the lowest 10%.
This is the 10th percentile, which is X when Z has a pvalue of 0.1. So X when Z = -1.28.
The highest total cholesterol level a man in this 35–44 age group can have and be in the lowest 10% is 160.59 milligrams per deciliter.