For this case we must find an expression equivalent to:
By definition of power properties we have to meet:
Then, we can rewrite the expression as:
Answer:
An electronics retailer receives a shipment of 6,000CDs to distribute to its stores. A quality control manager inspects a random
2 answers:
Answer: 300
Step-by-step explanation:
Given , An electronics retailer receives a shipment of 6,000CDs to distribute to its stores.
i.e, Total CD's he has now = 6,000
Also, a quality control manager inspects a random sample(S) of 40CD's , the number of defective(D) CD's are 2.
Then , the proportion of defective( D) CD's =
Now , the number of CDs in the shipment are likely to be defective = ( Total CD's) x (proportion of defective CD's)
= 6000 x 0.05
=300
Hence, the number of CDs in the shipment are likely to be defective =300
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Answer:
In summation form
Step-by-step explanation:
Within one hour, the first person gives a stack of flyers to six people and within the next hour, those six people give a stack of flyers to six new people.
So, in the first 5 hours, the summation of people that receive a stack of flyers not including the initial person will be given by
6 + (6 × 6) + (6 × 6 × 6) + (6 × 6 × 6 × 6) + (6 × 6 × 6 × 6 × 6).
So, in summation form
Therefore, Sigma-Summation Underscript n = 1 Overscript 5 EndScripts 6 (6) Superscript n minus 1, gives the correct solution. (Answer)