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3 years ago

Drag each figure to show if it is similar to the figure shown or why it is not similar

Mathematics

2 answers:

pogonyaev3 years ago

8 0

similar-6x3, 5x3, 12x15
not similar;different shapes-9x15, 3x5
not similar;different types of ratios-3x4

Bas_tet [7]3 years ago

6 0

Answer:

this box will show you the answer

Step-by-step explanation:

Thank Natalie222 for the answer its 6x10 not 6x3 :3

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Shopping online, you find a skateboard that costs $124.99, which is $42.50 less than the price at a local store. Write and solve

bulgar [2K]

the equation you would use is 124.99+42.50=X

X =167.49

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3 years ago

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PLEASE HURRY AND HELP!!!

shutvik [7]

Answer:

5.5%

Step-by-step explanation:

The absolute error: 34.5-32.7=1.8

Percentage error: Relative error * 100%

To get the relative error, you can calculate it by (absolute error)/(actual value) or (max error)/(measured value)

Since you only have the absolute error and actual value, let's calculate it using that method.

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4 0

3 years ago

Use addition to solve the linear system of equations. Include all of your work in your final answer.

love history [14]

We have that
x - y = 4-------> multiply by -1-----> -x+y=-4-----> equation 1
x+ 2y = 4------> equation 2

add equation 1 and equation 2
-x+y=-4
x+2y=4
-----------------
0+3y=0-----> y=0
x+2y=4------> x+0=4------>x=4

the solution is the point (4,0)

4 0

3 years ago

PLEASE WILL MARK BRANLIEST AND IS WORTH 20POINTS!!!!!

svlad2 [7]

Answer:

(3,-2)

Step-by-step explanation:

Part A:

1) Isolate x in x - y = 5

x = y + 5

2) Substitute that x into 4x+y=10

4(y + 5) + y = 10

4y + 20 + y = 10

5y = 10-20

5y = -10

y = -2

3) Use y to solve for x:

x = -2 + 5

x = 3

Part B:

Verify using results from Part A

3 - (-2) = 5

4(3) + (-2) = 12 - 2 = 10

Part C:

Just graph the equations and see where they intersect, which is exactly (3,-2). We got that in Part A and B

3 0

4 years ago

Please help me to solve this . Thank you so much .

worty [1.4K]

Answer:

a) N

b) L

c) area I

d) area II

e) area VI

Step-by-step explanation:

a) the points that are 2cm from R are Q, N, M, S. Then, points that are 4cm from P are K, N, R. So, the only one point that works for both is N.

b) the points that are >2cm from R are P, K, L, T. We do not count those are exactly 2cm from R. Then, points that are 4cm from T are R, M, L. Ans is L.

c) <4cm from P, are area I and II. Then area that are >2cm from R are I, VI, and V. So, the only area that works for both is I.

d) <2cm from R, are areas II, III, and IV. Then, <4cm from P, are areas I and II. So, the only one works for both is area II.

e) >4cm from T, are areas I, II, III, VI. Then, >4cm from P, are III, IV, V, VI. Finally, >2cm from R, are areas I, VI, V. The only one that works for all three conditions is area VI.

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3 years ago