Question

A rectangles length is three more than twice the width. The perimeter of the rectangle is 72 units. Write a let statement that can be used to find the length and width of the rectangle. Write an equation that can be used to find the length and width of the rectangle. Solve the equation. What is the length of the rectangle? What is the width of the rectangle?

Answer 1

Answer:

The length is 25 units and the width is 11 units

Step-by-step explanation:

Let the length of the rectangle be l.

Let the width of the rectangle be w.

We are given that the length of the rectangle is three times more than twice its width. This means that:

l = 3 + 2w

The perimeter of a triangle is given as:

P = 2(l + w)

This implies that:

P = 2[(3 + 2w) + w]

P = 2(3 + 3w)

We can use this to find the width of the rectangle and then the length.

The perimeter of the rectangle is 72 units.

Therefore:

72 = 2(3 + 3w)

72 = 6 + 6w

=> 6w = 72 - 6 = 66

w = 66 / 6 = 11 units

The length, l, is therefore:

l = 3 + 2(11) = 3 + 22 = 25 units