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3 years ago

-3 1/2 - (12 1/4) simplify this question

1 answer:

5 0

That would be -3 2/4 - 12 1/4 so the answer would be -15 3/4. If this is right could you possibly give me brainliest? Hope this helped.

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Solve for x:x-2=30 1)28 2)-28 3)-32 4)32

Jet001 [13]

The answer is number 4. (32). 32-2=30

6 0

4 years ago

The probability of a randomly selected adult in one country being infected with a certain virus is 0.005. In tests for the viru

myrzilka [38]

Answer:

The probability is 12.66%.

This is a low probability, so it is unlikely for such a combined sample to test positive.

Step-by-step explanation:

If the probability of being infected is 0.005, the probability of not being infected is 0.995.

Then, to find the probability of at least one of the 27 people being infected P(A), we can find the complementary case: all people are not infected: P(A').

$P(A') = 0.995^{27}$

$P(A') = 0.8734$

Then we can find P(A) using:

$P(A) + P(A') = 1$

$P(A) = 1 - 0.8734$

$P(A) = 0.1266 = 12.66\%$

This is a low probability, so it is unlikely for such a combined sample to test positive.

6 0

4 years ago

Arabic is an ex samplabusbbd Naina!;;!?!!!?!! back; have a joke bc no bc b

Nezavi [6.7K]

Availability bs night Bc has a joke

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3 years ago

How many ways can a committee of 6 be selected from a club with 10 members

Ratling [72]

Answer:

210

Step-by-step explanation:

The general formula for picking k items from a total of n is

$_{n}C_{k} = \frac{n! }{(n-k)!k! }$

Thus, if we want to select a committee of six people from a club with 10 members, the number of combinations is

$_{10}C_{6} = \frac{10! }{(10-6)!6! }$

$= \frac{10! }{4!6! }$

$= \frac{10\times9\times8\times7}{4\times3\times2\times1 }$

$= \frac{5040 }{24 }$

= 210

The committee can be selected in 210 separate ways.

4 0

3 years ago

Help with graph please

Ymorist [56]

Answer:

SO... not so tricky just go up by 10! 1= 10 2= 20 and make the y axis go up to ten. Also reverse the 10 and 1000 in your bottom x axis.

4 0

3 years ago